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Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
B is dominant.
Well considering that chestnut is recessive the foal most likely would be black, although it could be possible to get a bay foal.
the offspring will have both black and whit feathers.
Assuming black allele exhibits complete dominance and the white allele is recessive, the genotype is Bb.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
Genotype is the coded for traitPhenotype is the visible characteristicSo in the case where both parents had heterozygous dominant Brown eyes (Bb - big B for brown, dominant gene; little b for blue recessive gene); it is possible for the child to have blue eyes, by being homozygous recessive (bb).However this is an educated guess, as your question does not make sense.
If both parents have the same phenotype, but the offspring did not share that phenotype, then it is likely that the parents have a dominant phenotype, but the offspring has a recessive phenotype, which means that the offpring's genotype would be homozygous recessive, and it's parents' genotypes would be heterozygous. For example, the parents may both have the genotype Bb, which gives them black fur. Approximately 25% of their offspring should have the genotype bb, which gives them the phenotype of white fur.
The phenotype will show the dominant trait. All dominant traits mask recessive ones; If the genotype is heterozygous (One dominant and one recessive) the organism's phenotype will be dominant.
B is dominant.
Well considering that chestnut is recessive the foal most likely would be black, although it could be possible to get a bay foal.
the offspring will have both black and whit feathers.
The probable genotype for the white mouse would be homozygous recessive.
Phenotype: Black Bear x Brown Bear Genotype: BB x bb Possible gametes: B B b b Possible B B crosses: b Bb Bb b Bb Bb Phenotype of offspring: Only Black bears
It would look like this. --¦ W W -------------- w¦ Ww Ww w¦ Ww Ww All the offspring would be black-furred, all carrying one dominant gene and one recessive.
Well, in order for us to get a accurate genotype, we would need to know the parents. What are their traits?