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How do you use the Gibbs free energy equation to find the Gibbs free energy change for the formation of nitrosyl chloride?
-54.6 kJΔG = (-1218.3) - (298)(-29.9)(1/1000)**apex**-225.3 kjδg = (-905.4) - (298)(180.5)(1/1000)29.54 kJΔG°rxn = (1 mol)(65.27 kJ/mol) + (2 mol)(-33.56 kJ/mol) - (1 mol)(-50.72 kJ/mol) - (4 mol)(238.3 kJ/mol)
How do you use the Gibbs free energy equation to find the Gibbs free energy change for the oxidation of iron at 25 degrees C?
The Gibbs free energy change is calculated from the expressionΔ G = Δ H - T(Δ S)For the oxidation of iron, assuming you mean heating iron in air, where the product is black iron oxide,3Fe + 2O2 --> Fe3O4you need to find the enthalpy and entropy changes, which areΔ H (formation) = - 1118.4 kJ/molΔ S (formation) = - 345.5 J/mol/KSubstituting into the first equation, remembering to divide the entropy value by 1000 because it's in J per mol per kelvin, not kJ, and converting the 25 degrees C to kelvin, we get:Δ G = -1118.4 kj - 298 (- 345.5)/1000 kJ= - 1015.441 kJhttp://www.docbrown.info/page07/delta3SGc.htmΔ
What statement describes a reaction at 298 K if H 31 kJmol S 0.093 kJ(molK)?
It is not spontaneous.
Which direction of the reaction is favored at 298 K (room temperature)?
Toward I2(s) production
What state is oxygen at 298 K?
gas
Using Gibbs free energy equation what is the Gibbs free energy change for the synthesis of carbon disulfide at 25C?
δg = (-992.0) - (298)(-294.6)(1/1000)
How do you use the Gibbs free energy equation to find the Gibbs free energy change for the formation of nitrosyl chloride?
-54.6 kJΔG = (-1218.3) - (298)(-29.9)(1/1000)**apex**-225.3 kjδg = (-905.4) - (298)(180.5)(1/1000)29.54 kJΔG°rxn = (1 mol)(65.27 kJ/mol) + (2 mol)(-33.56 kJ/mol) - (1 mol)(-50.72 kJ/mol) - (4 mol)(238.3 kJ/mol)
How do you use the Gibbs free energy equation to find the Gibbs free energy change for the oxidation of iron at 25 degrees C?
The Gibbs free energy change is calculated from the expressionΔ G = Δ H - T(Δ S)For the oxidation of iron, assuming you mean heating iron in air, where the product is black iron oxide,3Fe + 2O2 --> Fe3O4you need to find the enthalpy and entropy changes, which areΔ H (formation) = - 1118.4 kJ/molΔ S (formation) = - 345.5 J/mol/KSubstituting into the first equation, remembering to divide the entropy value by 1000 because it's in J per mol per kelvin, not kJ, and converting the 25 degrees C to kelvin, we get:Δ G = -1118.4 kj - 298 (- 345.5)/1000 kJ= - 1015.441 kJhttp://www.docbrown.info/page07/delta3SGc.htmΔ
Which direction of the reaction is favored at 298 K?
Toward I2(s) production
Which compound is formed from its elements by an exothermic reaction at 298 K and 101.3 kPa?
H2O(g)
Which equation represents an exothermic reaction at 298 K?
C(s)+O2(g) -> CO2(g)
What form a spontaneous reaction at 298 K?
H = 28 kJ/mol, S = 0.109 kJ/(molK)
What statement describes a reaction at 298 K if H 31 kJmol S 0.093 kJ(molK)?
It is not spontaneous.
What is the phone number of the Cogswell Free Library in Orwell?
The phone number of the Cogswell Free Library is: 315-298-5563.
Which statement describes a reaction at 298 K if H 31 kJ mol S 0.093 kJ molK?
It is not spontaneous.
What are the factors of 298?
The factors of 298 are: 1, 2, 149, 298
How much is 30 percent percent off of 298?
30% off of 298= 30% discount applied to 298= 298 - (30% * 298)= 298 - (89.40)= 208.60
