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The gravitational force between two (2) bodies of masses m1 and m2 separated by a distance, r, is given by the equation

F= G(m1m2) / r2

(G= Gravitational constant 6.692 x 10-11 Nm2 kg-2 )

F= G(mpme) / r2

F= (6.692 x 10-11) (1.673 x 10-27 x 9.109 x 10-31) / (5.292 x 10-11)2

= 3.631 x 10-47 N

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Q: What is the gravitational force of an electron in hydrogen atom orbits nucleus at distance of 0.5292 A?
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Is there a stronger gravitational force acting on the particles of a hydrogen nucleus or a uranium nucleus?

No gravitational forces are implicated.


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The nucleus and the electron both revolve around a common center of charge. The only atom with equal charge in both places is hydrogen. Every atom heavier than hydrogen has more charge in the nucleus than there is on an electron. By the time you get to uranium, there is more than 90 times as much charge in the nucleus as there is on an electron, so the common center of charge is many times farther from each electron than it is from the nucleus. Also, each nuclear particle ... each proton and neutron ... is almost 2000 times more massive than an electron, and the same argument applies to the center of mass in the case of orbits governed by gravitational force, such as the solar system. But in the atom, the electrical forces completely dominate over the gravitational forces (by something like 1040.)


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