Want this question answered?
Use the formula potential energy = mgh (mass x gravity x height), mass in kilograms, gravity about 9.8 (meters per square second), height in meters. Answer will be in Joules.
Assuming that the gun is fired parallel to the ground, the bullet will begin to fall the instant that it leaves the muzzle. The total fall will be 200 meters. You will need to calculate how long it will take an object to fall 200 meters (hint- about 9.753 meters per second per second- or 9.753 meters the first second, 19.50 meters during the second second, etc) THEN multiply the velocity of the bullet (643 meters/ second) by the number of seconds it is in flight. That will be the distance when it hits the ground.
Dropped objects hit the ground at the same time (as long as they're dropped from the same height) because the acceleration of gravity is constant. On earth, it's 9.8 meters per second (32.2 feet per second) every second.
Impact velocity depends on the mass of the object and the height it falls from. It is the speed at which the acceleration due to gravity is maximized.
In free fall an object regardless of its mass will accelerate at 9.8 meters/second/second or 32 feet/second/second assuming that you are on earth in a frictionless environment. This means that any two objects regardless of their mass will fall to the ground at the same rate.
20 meters per second
The speed of an object falling from a great height is measured in meters per second per second until it reaches terminal velocity (maximum downward speed).
per second per second is taken with the context of how an object is changing its acceleration. An object accelerates by speeding up or slowing down. If an object speeds up, it could speed up at a rate of 5 meters per hour, let's say, every second. So after one second, its speed is 5 mph; after two seconds, its speed is 10 mph and so forth. If an object's speed is increasing at 5 meters a second, then its speed is 5 meters per second the first second; 10 meters per second the second second and so forth. We would say the object's acceleration is 10 meters per second / per second.AnswerIt has to do with speed,the time an object falls from a given height is calculated in seconds per second( it fell in less than a second)
It depends on the height of the building and also on the direction the object is thrown in (up, down etc.).
This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.This is completely unrelated to the height. An object at that mass, and speed, can be at any height.
593 meters.
1000000 m
Use the formula potential energy = mgh (mass x gravity x height), mass in kilograms, gravity about 9.8 (meters per square second), height in meters. Answer will be in Joules.
The object will be moving at 14.7 meters per second. 1.5 seconds X 9.8 meters per second squared(the gravitational constant). This assumes that the object's original velocity is zero.
Assuming that the gun is fired parallel to the ground, the bullet will begin to fall the instant that it leaves the muzzle. The total fall will be 200 meters. You will need to calculate how long it will take an object to fall 200 meters (hint- about 9.753 meters per second per second- or 9.753 meters the first second, 19.50 meters during the second second, etc) THEN multiply the velocity of the bullet (643 meters/ second) by the number of seconds it is in flight. That will be the distance when it hits the ground.
The height, in feet, above the ground at time t, H(t) = 40 + 32*t - 16*t2
17.8 meters