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What is the horizontal component of the initial velocity of the ball?
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A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
What happens to the horizontal velocity of a ball after it rolls off a table?
The horizontal velocity will be equal to the translational velocity of the ball right before it falls off the table. ============================== When we do exercises that deal with the behavior of the ball after it leaves the edge of the table, we always ignore air resistance. When we do that, the horizontal component of velocity remains constant forever, or at least until the ball hits something.
The horizontal and vertical components of the initial velocity of a tennis ball are 18.2 ms and 21.3 ms respectively what is the magnitude of the initial velocity of the ball?
To take the magnitude of the velocity you will need to square both the horizontal and vertical components and then take the square root of their sum. So: V=(Vx2+Vy2)1/2
Ball kicked into the air at an angle of 34.0 degrees above the horizontal the initial velocity of the ball is 25.0 ms How long is the soccer ball in the air?
the soccer ball in the air is at 56.o speed
What are the two types of motion a projectile has?
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
Will a ball drop rest reach the ground quicker than the one lunched from the same height but with and initial horizontal velocity?
No. What counts in this case is the vertical component of the velocity, and the initial vertical velocity is zero, one way or another.
A ball is thrown horizontally from a window on the second floor of a building What is the vertical component of its initial velocity?
If a ball is thrown horizontally from a window on the second floor of a building, the vertical component of its initial velocity is zero.
What happens to the horizontal velocity of a ball after it rolls off a table?
The horizontal velocity will be equal to the translational velocity of the ball right before it falls off the table. ============================== When we do exercises that deal with the behavior of the ball after it leaves the edge of the table, we always ignore air resistance. When we do that, the horizontal component of velocity remains constant forever, or at least until the ball hits something.
The horizontal and vertical components of the initial velocity of a tennis ball are 18.2 ms and 21.3 ms respectively what is the magnitude of the initial velocity of the ball?
To take the magnitude of the velocity you will need to square both the horizontal and vertical components and then take the square root of their sum. So: V=(Vx2+Vy2)1/2
Ball kicked into the air at an angle of 34.0 degrees above the horizontal the initial velocity of the ball is 25.0 ms How long is the soccer ball in the air?
the soccer ball in the air is at 56.o speed
How does newton's first law effect soccer?
When a ball is kicked at an angle, there is no acceleration along the horizontal direction (since there isn't any force along the direction ,ignoring viscous forces), so , its velocity along the horizontal direction remains unchanged.... according to the 1st law , velocity changes only when a net resultant force is applied on the ball , so , Newton's law is valid. only the initial angle of kick and the vertical component of velocity are mainly responsible for the distance travelled by the ball horizontally....
What are the two types of motion a projectile has?
If you throw ball at an angle above horizontal, you will see the path of the ball looks like an inverted parabola. This is result of the fact that the ball's initial velocity has a horizontal and vertical component. If we neglect the effect of air resistance, the horizontal component is constant. But the vertical component is always decreasing at the rate of 9.8 m/s each second. To illustrate this, let the initial velocity be 49 m/s and the initial angle be 30˚. Horizontal component = 49 * cos 30, Vertical = 49 * sin 30 = 24.5 m/s As the ball rises from the ground to its maximum height, its vertical velocity decreases from 24.5 m/s to 0 m/s. As the ball falls from its maximum height to the ground, its vertical velocity decreases from 0 m/s to -24.5 m/s. Since the distance it rises is equal to the distance it falls, the time that it is rising is equal to the time it is falling. This means the total time is equal to twice the time it is falling. This is the reason that the shape of the ball's path is an inverted parabola. At the maximum height, the ball is moving horizontally. If you do a web search for projectile motion, you will see graphs illustrating this.
If i throw a ball downward from a window at a speed of 2.5 ms How fast will it be moving when it hits the sidewalk 3.0 m below?
This would be the simple answer, ignoring air resistance, wind, and other such incooperative forces. First working out the vertical component of velocity when it hits the floor: final velocity (v) = ? Initial velocity (u) = 0 Displacement (s) = 3 Accelleration (a) = g; taken to be 9.81 Using the equationof linear motion v2 = u2 + 2as v2 = 0 + (2 * 9.81 * 3) v2 = 58.86 v = 7.672 Now we know that the horizontal component of velocity will be 2.5 ms-1 (ignoring air resistance) so now we have to find out the velocity of the ball when it hits the floor, if it is travelling at a velocity with a downwards vertical component of 7.672ms-1 and a horizontal component of 2.5ms-1 2.52 + 7.6722 = 65.1095 Square rooting that... Velocity = 8.069ms-1
What is initial velocity of the ball as the child lets it go at the top of a driveway?
The initial velocity is 0 metres/second.
A player kicks a soccer ball from ground level and sends it flying at an angle of 30 degrees?
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A ball is thrown straight up At the top of its path its instantaneous speed is?
If it is thrown at an angle, at the top of its path, its vertical velocity will be zero, however its horizontal velocity will be the same as its initial horizontal velocity minus whatever loss in speed as a result of air friction at that point. We won't know what that is without more information.
A golfer tees off and hits a golf ball at a speed of 31 ms and at an angle of 35 degrees. What is the vertical velocity component of the ball Round the answer to the nearest tenth of a ms.?
the vertical component of the balls initial velocity is Ay= 48 sin 45 34m/s
