Iron's atomic symbol is Fe. Iodine's atomic symbol is I. There is no iron in that molecule. ICl5 is a molecule not an atom. As for the hybridization i would suggest you drop your chem class if you don't know basic fundamentals of atomic symbols and the difference between molecules and atoms
The hybridization of ICL5 (iodine pentafluoride) is sp3d2, as it has 5 regions of electron density around the iodine atom (1 lone pair and 5 bonding pairs). This corresponds to the promotion of electrons from the 5s and 5p orbitals into the 5 d orbitals to form six equivalent sp3d2 hybrid orbitals.
The boron atom in BF3 has sp2 hybridization.
The carbon atom in CF4 has a hybridization of sp3.
The hybridization of the central atom in NCl3 is sp3.
The hybridization of the nitrogen atom in N2O is sp.
The hybridization of the sulfur atom in H2SO3 is sp2.
The central atom in the molecule CH3NCO has sp2 hybridization.
To find the hybridization of an atom, you can use the formula: hybridization number of sigma bonds number of lone pairs on the atom. Count the sigma bonds and lone pairs, then determine the hybridization based on the total.
To determine the orbital hybridization of an atom in a molecule, you can look at the atom's steric number, which is the sum of the number of bonded atoms and lone pairs around the atom. The hybridization is determined by the steric number according to the following guidelines: Steric number 2: sp hybridization Steric number 3: sp2 hybridization Steric number 4: sp3 hybridization Steric number 5: sp3d hybridization Steric number 6: sp3d2 hybridization By identifying the steric number, you can determine the orbital hybridization of the atom in the molecule.
The hybridization state of each carbon atom in nemotin is sp3.
The circled atom in the molecule is best described by sp3 hybridization.
To determine the hybridization of the central atom in a molecule, you can use the formula: hybridization number of sigma bonds number of lone pairs on the central atom. Count the number of sigma bonds and lone pairs around the central atom, then use this formula to find the hybridization.