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If you mean the triiodide ion I3-, then: I3- is a linear anion. there are 5 electron pairs around the central I atom which according to VSEPR theory form a trigonal bipyramid. The hybridisation is said to be dsp3 .
3.
Linear. It actually exists as I3- meaning that one of the iodines has an extra electron. Putting the extra electron at the central iodine atom gives you two bond pairs and three lone pairs, for a steric number of 5. Linear. It actually exists as I3- meaning that one of the iodines has an extra electron. Putting the extra electron at the central iodine atom gives you two bond pairs and three lone pairs, for a steric number of 5.
When I- ions are merged with iodine molecules, a complex of I3- is formed which is stable in an aqueous medium.
Iodine does not solve particulary well in polar solvents like water because it is not -and cannot form- one or more ions in solution. The solubility increases much by the 'help' of 'co-soluted' iodide ions (I-) according to: I- + I2 --> I3- (so-called Iodine-Iodide complex ions)
If you mean the triiodide ion I3-, then: I3- is a linear anion. there are 5 electron pairs around the central I atom which according to VSEPR theory form a trigonal bipyramid. The hybridisation is said to be dsp3 .
It's linear, but the middle I has 6 electron pairs instead of only 4.
3.
Iodine (I2) reacts with iodide (I-) to form triiodide ion (I3-). Although I2 is insoluble in water, I3-is very soluble, so adding KI will pull I2into solution is I3-.
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Linear. It actually exists as I3- meaning that one of the iodines has an extra electron. Putting the extra electron at the central iodine atom gives you two bond pairs and three lone pairs, for a steric number of 5. Linear. It actually exists as I3- meaning that one of the iodines has an extra electron. Putting the extra electron at the central iodine atom gives you two bond pairs and three lone pairs, for a steric number of 5.
Iodine itself, I2 is not very soluble in water. However, the solubility of iodine can be greatly increased by adding potassium iodide to the reaction. The potassium iodide is broken apart into K+ and I-. The potassium ion is then dissolved into the water, and the iodine ion reacts with the I2 to form I3-. This I3- molecule is soluble in water. Therefore, the solubility is relative because I2 is not very soluble, but I3- is soluble, and both are made of nothing but iodine. Hope this helps.
Yes, by example:iodide ion and iodine molecule to form a complex ion:I- + I2 --> I3-
I3- is known as the triiodide ion (or sometimes tri-iodide ion, for better readability). It arises in equilibrium when elemental iodine (I2) and the iodide ion (I-) are both present.
If you're referring to I3- The shape is Linear. The central I has 3 lone pair arounds it, with 2 bonded atoms.
It might be because iodide and iodine is in an equilibrium: I2 + I- -> I3- That way formed iodine won't escape when an excess of iodide is used.
Add some mildly acid Iodide to the hypo chlorite solution.Titrate the formed Iodine-Iodide complex (I3-) with disodium thiosulfate until the starch (added at almost the end) color (black-blue with Iodine-Iodide complex) is disappeared.ClO- + Cl- + 2 H+ --> 'Cl2'available + H2O'Cl2'available + 3 I- --> 2 Cl- + I3-I3- + 2 S2O32- --> 3 I- + S4O62-(There are official -standard- Analytical Methods and Testing Procedures available on this subject).