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In this compound, the carbon atoms undergo sp3 hybridization.
BeBr2 is the chemical formula of beryllium bromide.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
Depends on the compound under consideration. sp hybridization in nitriles, sp2 in imines, sp3 in ammonia or amines. The Textbook, 'Organic Chemistry' by John E. McMurry or by L. G. Wade will you more examples of hybridization of heteroatoms.
If the given compound exists, there'll be 4 sigma bonds and a single remaining electron in the valence shell of the central atom. With 5 activation groups, the hybridization would be sp3d.
This compound is beryllium bromide.
BeBr2 , as a compound of Beryllium (Be) as a formal Be2+ and Bromine (Br) as a bromide ion (Br-)would be referred to as Beryllium Bromide. There is no requirement to call it beryllium dibromide, as beryllium only exhibits 2+ cations under normal conditions, so the only realistic compound of these elements is BeBr2.
In this compound, the carbon atoms undergo sp3 hybridization.
The compound is Calcium Oxide and is commonly known as Quick Lime.
Not quite sure what Hybridization means here, yet No; the only requirement for a compound to be Organic is that it contains Carbon.
tima is such a stupidhead.
trigonal bipyramidal
BeBr2 is the chemical formula of beryllium bromide.
BeBr2 is the chemical formula of beryllium bromide.
There wont be a stable compound with the formula C2Br2. If there is then it will be sp hybridization of carbon. If the question is for CH2Br2, then carbon will be sp3 hybridized.
Beryllium Bromide
Depends on the compound under consideration. sp hybridization in nitriles, sp2 in imines, sp3 in ammonia or amines. The Textbook, 'Organic Chemistry' by John E. McMurry or by L. G. Wade will you more examples of hybridization of heteroatoms.