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[OH-] = 10-[14.0-pH] = 10-[14.0-4.72] = 10-9.28 = invlog(-9.28) = 5.25*10-10 mol/L

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13y ago
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14y ago

poor-hydrogen ion acceptor

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Q: What is the hydroxide-ion concentration of an aqueous solution having a pH of 4.72?
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