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A: The answer deviate from IC to ic . It is defined not as voltage but rather as unit loads. In other words there is a limit to how many inputs can be tied together along with how many units can be driven for reliable operation. So basically is a question of current sink and source for both input and output which strictly relates to reliable triggering voltage levels. If I remember i used the 8 for unit load for the input and 40 unit load for the output. These numbers are general use for design.
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Can you improve voltage level in the range of millivolt into a 15volt?
A voltage amplifier (high input and output impedances) with a gain of 83.5 dB will amplify a signal of 1 millivolt to an output of 15 volts.
Which voltages are supported by a Toshiba power supply?
The input voltage range for the Toshiba power supply is AC 100V - 240V. The output voltage is DC 19V / output current is 4.74A. This power supply comes with a power cord and packaging will state voltage recommended for the product.
How do you design a simple integrator with an op amp?
To design a simple integrator with an op amp, place a resistor and capacitor in series in the feedback loop, between output and inverting input. Place another resistor from circuit input to the inverting input. Ground the non-inverting input. The current through the input resistor will be balanced with the current through the feedback resistor. Since there is a capacitor also, the voltage slope at the output will be proportional to the current. If you want the capacitor to discharge faster in one direction, you can place a diode (and optional resistor) across the feedback resistor. This works because the capacitor resists a change in voltage, proportional to current, and inversely proportional to capacitance. The equation is dv/dt = i/c. This means that dv/dt is linear with constant i and c. In this configuration, a constant current input will be balanced with a linear voltage ramp on the output, limited only by the range of the op amp. Constrast this with a simple RC circuit - with constant voltage, the RC circuit will exhibit a logarithmic output. If, for instance, you were to drive this circuit with a square wave, the output would be triangular. With the diode, the output would be sawtooth.
What minimum information should be provided when describing an arc welding machine?
Power supply (Single or Three Phase /AC or DC) Input Voltage frequency Input power capacity Output current range No load voltage Peak current range Base current Arc force Efficiency Power factor Protection class Insulation class gross weight Dimension Packing dimension.
What is voltage of TTL circuit?
CMOS gate circuits have input and output signal specifications that are quite different from TTL. For a CMOS gate operating at a power supply voltage of 5 volts, the acceptable input signal voltages range from 0 volts to 1.5 volts for a "low" logic state, and 3.5 volts to 5 volts for a "high" logic state. "Acceptable" output signal voltages (voltage levels guaranteed by the gate manufacturer over a specified range of load conditions) range from 0 volts to 0.05 volts for a "low" logic state, and 4.95 volts to 5 volts for a "high" logic state:It should be obvious from these figures that CMOS gate circuits have far greater noise margins than TTL: 1.45 volts for CMOS low-level and high-level margins, versus a maximum of 0.7 volts for TTL. In other words, CMOS circuits can tolerate over twice the amount of superimposed "noise" voltage on their input lines before signal interpretation errors will result.CMOS noise margins widen even further with higher operating voltages. Unlike TTL, which is restricted to a power supply voltage of 5 volts, CMOS may be powered by voltages as high as 15 volts (some CMOS circuits as high as 18 volts). Shown here are the acceptable "high" and "low" states, for both input and output, of CMOS integrated circuits operating at 10 volts and 15 volts, respectively:The margins for acceptable "high" and "low" signals may be greater than what is shown in the previous illustrations. What is shown represents "worst-case" input signal performance, based on manufacturer's specifications. In practice, it may be found that a gate circuit will tolerate "high" signals of considerably less voltage and "low" signals of considerably greater voltage than those specified here.Conversely, the extremely small output margins shown -- guaranteeing output states for "high" and "low" signals to within 0.05 volts of the power supply "rails" -- are optimistic. Such "solid" output voltage levels will be true only for conditions of minimum loading. If the gate is sourcing or sinking substantial current to a load, the output voltage will not be able to maintain these optimum levels, due to internal channel resistance of the gate's final output MOSFETs.Within the "uncertain" range for any gate input, there will be some point of demarcation dividing the gate's actual "low" input signal range from its actual "high" input signal range. That is, somewhere between the lowest "high" signal voltage level and the highest "low" signal voltage level guaranteed by the gate manufacturer, there is a threshold voltage at which the gate willactuallyswitch its interpretation of a signal from "low" or "high" or vice versa. For most gate circuits, this unspecified voltage is a single point:
Can you improve voltage level in the range of millivolt into a 15volt?
A voltage amplifier (high input and output impedances) with a gain of 83.5 dB will amplify a signal of 1 millivolt to an output of 15 volts.
Why clipping happen for op-amp?
Clipping occurs in the voltage waveform when the input voltage, multiplied by the voltage gain of the op-amp circuit, exceeds the op-amp supply voltage as limited by the output network. The supply voltage and output network, limits the maximum voltage that can be achieved at the output. The op-amp behaves normally within its range of maximum voltage output, and then it is clipped when it reaches the maximum voltage of the circuit.
Which voltages are supported by a Toshiba power supply?
The input voltage range for the Toshiba power supply is AC 100V - 240V. The output voltage is DC 19V / output current is 4.74A. This power supply comes with a power cord and packaging will state voltage recommended for the product.
What is an output voltage swing?
Output voltage swing is defined as the maximum positive or negative peak output voltage that can be obtained without wave form clipping, when quiescent DC output voltage is zero. VOM is limited by the output impedance of the amplifier, the saturation voltage of the output transistors, and the power supply voltages. This is depicted in the figure above. This emitter follower structure cannot drive the output voltage to either rail. Rail-to-rail output op amps use a common emitter (bipolar) or common source (CMOS) output stage. With these structures, the output voltage swing is only limited by the saturation voltage (bipolar) or the on resistance (CMOS) of the output transistors, and the load being driven.Maximum and minimum output voltage is usually a design issue when dynamic range is lost if the op amp cannot drive to the rails. This is the case in single supply systems where the op amp is used to drive the input of an ADC, which is configured for full scale input voltage between ground and the positive rail. Because newer products are focused on single supply operation, datasheets use the terminology VOH and VOL to specify the maximum and minimum output voltage.
What is output swing of an op amp?
Output voltage swing is defined as the maximum positive or negative peak output voltage that can be obtained without wave form clipping, when quiescent DC output voltage is zero. VOM is limited by the output impedance of the amplifier, the saturation voltage of the output transistors, and the power supply voltages. This is depicted in the figure below. This emitter follower structure cannot drive the output voltage to either rail. Rail-to-rail output op amps use a common emitter (bipolar) or common source (CMOS) output stage. With these structures, the output voltage swing is only limited by the saturation voltage (bipolar) or the on resistance (CMOS) of the output transistors, and the load being driven. Maximum and minimum output voltage is usually a design issue when dynamic range is lost if the op amp cannot drive to the rails. This is the case in single supply systems where the op amp is used to drive the input of an ADC, which is confiured for full scale input voltage between ground and the positive rail.
What is the range of the sine function?
The domain (input) is all possible angles. The range (output) is -1 to +1.
What is an input or output of a continuosly variable signal within a designated range?
The input or output of a continuously variable signal within a designated range is a sampled data or a feedback system. This accepts limited analog signal and encodes.
What is the difference of a fixed regulator from an adjustable regulator?
A fixed voltage regulator outputs only one specific voltage. An adjustable voltage regulator can be adjusted to output any voltage from the range it was designed for by changing the output resistors.
What is the voltage output on a 2000 ford windstar?
Normal voltage, checking at the battery or alternator should be in the 14 range.
What is the function of Voltage regulator in ride on mower?
Voltage regulator ensures a proper good quality voltage is applied to the ride on mower irrespective of the poor quality of input voltage. Of course voltage regulators have limitations too and work well with in a range of input voltage.
How do you describe the domain and range of a function?
The domain is the set of values of the input while the range is the set of output values.
How do you design a simple integrator with an op amp?
To design a simple integrator with an op amp, place a resistor and capacitor in series in the feedback loop, between output and inverting input. Place another resistor from circuit input to the inverting input. Ground the non-inverting input. The current through the input resistor will be balanced with the current through the feedback resistor. Since there is a capacitor also, the voltage slope at the output will be proportional to the current. If you want the capacitor to discharge faster in one direction, you can place a diode (and optional resistor) across the feedback resistor. This works because the capacitor resists a change in voltage, proportional to current, and inversely proportional to capacitance. The equation is dv/dt = i/c. This means that dv/dt is linear with constant i and c. In this configuration, a constant current input will be balanced with a linear voltage ramp on the output, limited only by the range of the op amp. Constrast this with a simple RC circuit - with constant voltage, the RC circuit will exhibit a logarithmic output. If, for instance, you were to drive this circuit with a square wave, the output would be triangular. With the diode, the output would be sawtooth.
