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when the input arm is smaller than the output arm.
The MA would be 6cm because the formula to find the MA is input arm divided by output arm
1.25
That's a Class-1 lever, where the input and output are on opposite sides of the fulcrum.
the input arm is in science, it may also be called an effort arm. it is the side of a lever that u apply the froce on
when the input arm is smaller than the output arm.
The end of a lever that carries the load is the output arm instead of the input arm which is the end of a lever that force is applied to move the load.
Yes
The MA would be 6cm because the formula to find the MA is input arm divided by output arm
1.25
3
Input
The third class lever functions between the input force and the output force
first class lever. Why? because it is in the order of output force-fulcrum-input force. output force ______________________________ input force fulcrum
That's a Class-1 lever, where the input and output are on opposite sides of the fulcrum.
Length of input arm (input force to the fulcrum) divided by the Length of the output arm (output force to the fulcrum)exampledin/dout=2cm/4cm=0.5in the example the IMA is 0.5
From the design of the lever (on paper), the mechanical advantage is effort arm/load arm which means Distance from pivot to the applied force/distance from pivot to the load The result of that is that the forces will have the reciprocal ratio, and the input force to the lever will be the output force/the Mechanical Advantage .