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The force at the input of a sprinkler can be found from F = PA; where P is the pressure of the water at the spigot or source of the water to the sprinkler and A is the x-sectional area of the input hose to the sprinkler.

EX: A typical house-hold water pressure is about P = 60 psi in the US. And a typical hose is a 1/2 inch diameter; so A = pi (D/2)^2 = pi (.5/2)^2 in^2 is the x-sectional area. Which means the force at the input would be F = PA = 60pi()(.5/2)^2 = 11.78097245 ~ 12 pounds of input force. ANS.

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Duane Anymouse

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4y ago

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