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What is the work output by a 92 percent efficient wheel and axle when 75 J of work is input?
0.92 x 75 J = 69 joules How did you get that answer
The efficiency of a ramp is 75 percent If the amount of work input is 240 J what is the amoun t of useful work output?
The formula for percent work efficiency is: percent efficiency = (work output/work input) x 100 To find the answer to this question, you just need to plug the given values into the formula. The problem tells you that the work input is 240 J and the percent efficiency is 75 %, so 75 = (work output/240) x 100 Now, solve for work output: -first divide by 100 .75 = (work output/240) -then multiply by 240 180 J = work output (in units of joules because work is measured in joules) And there's your answer. Hope this helped!
A mechanical device requires 420 j of work to do 230 j of work in lifting a crate what is the efficiency of the device?
The efficiency is (output energy)/(input energy) = 340/400 = 85%
What is the output work of a machine when its efficiency is 62 percent and the input is 39 J?
Just divide the useful work done (the 90J) by the input work. If you want the result in percent, multiply by 100.
The efficiency that requires 100j of input to do 35 j of work?
I believe the answer is 35%. Since the formula for energy = useful work / total work input, you would then plug 35 j into the useful work and 100 under the total work input. You divide that and you get .35. Then, you multiply .35 by 100, and you get 35%.
What is the efficiency of an air conditioner if there is a work input of 320 J and a work output of 80 J?
Efficiency = (output/input) x 100 = (80/320) x 100 = 25%
What is the work output by a 92 percent efficient wheel and axle when 75 J of work is input?
0.92 x 75 J = 69 joules How did you get that answer
The efficiency of a ramp is 75 percent If the amount of work input is 240 J what is the amoun t of useful work output?
The formula for percent work efficiency is: percent efficiency = (work output/work input) x 100 To find the answer to this question, you just need to plug the given values into the formula. The problem tells you that the work input is 240 J and the percent efficiency is 75 %, so 75 = (work output/240) x 100 Now, solve for work output: -first divide by 100 .75 = (work output/240) -then multiply by 240 180 J = work output (in units of joules because work is measured in joules) And there's your answer. Hope this helped!
What is the application of rational algebraic expression in real life situation?
Manufacturing. A machine has a work output of 14ax4 j (joules) and a work in put 7a2x5 j. What is the eficiency of the machine? efficiency in % = work output in joules work input in joules
Inventor claims machine produces 120 J of work with an input of 110 J Is it believable?
It's not beleivable because a machine can't output more energy than is input to it.
How do you calculate output voltage?
output divided by input times 100 equals effiency. i.e.: 200 J of input energy and 10 J output energy calculates: 10/200 x 100%= 5%
A mechanical device requires 420 j of work to do 230 j of work in lifting a crate what is the efficiency of the device?
The efficiency is (output energy)/(input energy) = 340/400 = 85%
What is the rule when the input is 5 and the output is 2?
it depends on what the rest are. but logically, probably -3
If the boats engine has a heat input of 40000 J with 30000 J exhausted into the surroundings the heat sink what is its efficiency?
efficiency = output/input therefore, in above case it is 3/4= 0.75 or 75%.
What has the author I J Leontaritis written?
I. J. Leontaritis has written: 'Input-output parametric models for nonlinear systems'
What is the efficiency formula?
Efficiency=Useful energy output divided by the energy input. i.e. 100 J is the energy input and you get 5 J light energy from a lamp, the waste energy would be 5 J.
What is the output work of a machine when its efficiency is 62 percent and the input is 39 J?
Just divide the useful work done (the 90J) by the input work. If you want the result in percent, multiply by 100.
