The input work required depends on the efficiency of the system. If the system is 100% efficient, then the input work would also be 140 J. However, if the system is less than 100% efficient, then the input work would be higher than 140 J.
The amount of useful work output can be calculated by multiplying the work input by the efficiency. In this case, 240 J * 0.75 = 180 J. Therefore, the useful work output is 180 J.
The mechanical advantage is calculated by dividing the output force by the input force. In this case, the input work is 50 J and the output work is 200 J. The mechanical advantage would be 4, indicating that the output work is 4 times greater than the input work.
The efficiency of the ramp is 25%. This is calculated by taking the ratio of output work to input work, which in this case is 24 J / 96 J = 0.25, or 25%.
To calculate the output work of a machine, you can use the formula: Efficiency = (Output Work / Input Work) * 100%. Given that the efficiency is 62% and the input work is 39 J, you can rearrange the formula to solve for the output work. First, convert the efficiency to a decimal (62% = 0.62) and then plug in the values to find the output work. The output work of the machine would be 24.18 J.
The efficiency of the pulley system is calculated by dividing the output work by the input work and multiplying by 100, so efficiency = (output work/input work) * 100. In this case, the output work is 170 J and the input work is 250 J, so the efficiency is (170/250) * 100 = 68%.
The amount of useful work output can be calculated by multiplying the work input by the efficiency. In this case, 240 J * 0.75 = 180 J. Therefore, the useful work output is 180 J.
The mechanical advantage is calculated by dividing the output force by the input force. In this case, the input work is 50 J and the output work is 200 J. The mechanical advantage would be 4, indicating that the output work is 4 times greater than the input work.
The efficiency of the ramp is 25%. This is calculated by taking the ratio of output work to input work, which in this case is 24 J / 96 J = 0.25, or 25%.
Efficiency = (output/input) x 100 = (80/320) x 100 = 25%
To calculate the output work of a machine, you can use the formula: Efficiency = (Output Work / Input Work) * 100%. Given that the efficiency is 62% and the input work is 39 J, you can rearrange the formula to solve for the output work. First, convert the efficiency to a decimal (62% = 0.62) and then plug in the values to find the output work. The output work of the machine would be 24.18 J.
The efficiency of the pulley system is calculated by dividing the output work by the input work and multiplying by 100, so efficiency = (output work/input work) * 100. In this case, the output work is 170 J and the input work is 250 J, so the efficiency is (170/250) * 100 = 68%.
The efficiency of the system can be calculated using the formula: efficiency = (output work / input work) * 100%. In this case, the efficiency would be (123 J / 150 J) * 100% = 82%.
The efficiency of the boat's engine is calculated by dividing the useful work output by the total heat input. In this case, the useful work output would be 10000 J (40000 J input - 30000 J exhausted), and the total heat input is 40000 J. Therefore, the efficiency would be 10000 J / 40000 J = 0.25 or 25%.
0.92 x 75 J = 69 joules How did you get that answer
The formula for percent work efficiency is: percent efficiency = (work output/work input) x 100 To find the answer to this question, you just need to plug the given values into the formula. The problem tells you that the work input is 240 J and the percent efficiency is 75 %, so 75 = (work output/240) x 100 Now, solve for work output: -first divide by 100 .75 = (work output/240) -then multiply by 240 180 J = work output (in units of joules because work is measured in joules) And there's your answer. Hope this helped!
Efficiency is calculated by dividing the work output by the work input. In this case, the work output is the work done against gravity, which is 2000 N * 1m = 2000 J. Thus, the efficiency is 2000 J (work output) / 3000 J (work input) = 2/3 = 66.7%.
The efficiency of the street cleaner's engine is calculated by dividing the useful work output by the total heat input. In this case, the useful work output is the heat input minus the waste heat: 200,000 J - 150,000 J = 50,000 J. Therefore, the efficiency would be 50,000 J (useful work output) / 200,000 J (total heat input) = 0.25 or 25%.