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it isn't good enough, you forgot to put in the '^'s between the 'x' and 'y' and the 'dy'
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What is the integral of dy?
Ingetral(dy) = y + c (c is a constant. A point would have to be given to find the value of c.)
How do you differentiate xy equals logy c?
The differential of the product xy with respect to x is y + x dy/dx. The differential of logy with respect to x is (1/y) dy/dx. The role of c in this question is not made clear.
What is differential equation of x-y equals xy?
x - y = xydifferentiating wrt x1 - (dy/dx) = x(dy/dx) + y(x + 1)(dy/dx) + y + 1 = 0
Why do you divide by 3 to get the volume of a pyramid?
It comes from Calculus. You are integrating a function which has some form of y²dy {dy is the height of a tiny horizontal slice, which is the shape of a square which is area y²}. The integral of y²dy is y³/3
How do you Differentiate and Integrate y equals 3x?
dy/dx = 3 integral = (3x^2)/2
How do you calculate slope of a curve?
If the curve is on the xy-plane, finding an expression for dy/dx will give you the slope of a curve at a point.
What is the derivative of xy-2y equals 1?
To find the derivative of the equation xy - 2y = 1, differentiate each term with respect to x using the product rule for the first term and the power rule for the second term. This yields dy/dx = (1 - 2x).
What is the integral of 2?
The integral of 2 is "who gives a $%&#." You need to know what 2 is relating to and what the 2 means. If the question is "What is the integral of 2 dx" the answer would be "2x + c," with c being a constant. If you instead wish to know what the integral of 2 dy, the answer is very different. (2y +c)
How do you express an iterated integral in six different ways?
First, draw the region/solid being bounded by parameters say: y^2 + z^2 = 9, x = -2, and x = 2 Now analyze what possible iterated integrals can be used to find this region. the two "main" iterated integrals are: the triple integral from [-2,2] [-3,3] [-sqrt(9-y^2),sqrt(9-y^2)] dz dy dx and [-2,2] [-3,3] [-sqrt(9-z^2),sqrt(9-z^2)] dy dz dx Now, instead of sketching every region to find the different possible integrals, using the rules of triple integration, they will essentially be any legal alteration of the order of the "main" integrals. essentially, the first main integral can be rewritten as dx dz dy, and dz dx dy the second can be written as dx dy dz and dy dx dz.
Integral of sin square root x?
For ∫ sin(√x) dx let y = √x = x1/2 → dy = 1/2 x-1/2 dx → 2x1/2 dy = dx → 2y dy = dx → ∫ sin(x1/2) dx = ∫(sin y) 2y dy Now: ∫ uv dx = u∫v dx - ∫(u'∫v dx) dx → ∫(sin y) 2y dy = ∫2y sin y dy = 2y ∫sin y dy - ∫(2 ∫sin y dy) dy = -2y cos y + 2 sin y + C = 2 sin y - 2y cos y + C → ∫ sin(√x) dx = 2 sin(√x) - 2(√x) cos(√x) + C
What is xy minus xy?
xy - xy = 0
What is xy plus xy?
xy + xy = 2xy
