You need to know the voltage and the power factor in order to answer the question.
Since the breaker that is installed on the generator set will be sized to the output of the 30 kW generator, the load will stay connected until the thermal trip of the breaker trips the load off line. This will be in the matter of seconds before it happens. To handle a 75 kW load and depending if it is an inductive or a resistive load you will need at least a 80 to 100 kW generator.
Kw can be calculated from volts be using the formula p=(voltage)square/resistance*1000
Much to my dismay i found its an experimental value, depends on type of core, cooling tech, resistance of wiring etc.
hi.. this is pankaj working as power engineer. we have a 11 kw induction motor which is used in fluidising blower. its no load current i sarround 9.5 to 10.6 amp. and under load its ampere does nt exceed 15 amp. its winding resistance is 1.4 ohm.
thanks ,it should be 400amps.
0.0075 kw
It does not matter, when testing a generator with a resistive load bank, if you load it to kVA or KW. For a resitive load, i.e. non-reactive load, the power factor is one, so kVA and kW are the same.
Since the breaker that is installed on the generator set will be sized to the output of the 30 kW generator, the load will stay connected until the thermal trip of the breaker trips the load off line. This will be in the matter of seconds before it happens. To handle a 75 kW load and depending if it is an inductive or a resistive load you will need at least a 80 to 100 kW generator.
It depends on the total connected load (KW) of the house. If the total connected load is about 20 KW the alternator generator should be designed to meet peak 20 kw load
3phese 460 volt 75 kw a/c drivi full load current
Kw can be calculated from volts be using the formula p=(voltage)square/resistance*1000
It depends on the voltage. A load of 32 amps at 120 volts will be 3.84 kW. A load of 32 amps at 240 volts will be 7.68 kW. For any other voltage, multiply the voltage by 0.032. All these calculations assume a resistive (non-reactive) load.
Transformers are rated in VA or kVA. That is because the voltage is limited by the power loss in the magnetic core, and the current is limited by the power loss in the resistance of the windings. The rated voltage times the rated current gives the transformer's rating in kVA.
No because there are losses along the way. Some of the needed electrical power will go to control circuitry and inefficiencies in the heating elements themselves.
a: there is no calculated load for the range. This 16 kw is the maximum that this particular range can safely use any thing less is OK.
Much to my dismay i found its an experimental value, depends on type of core, cooling tech, resistance of wiring etc.
It could overheat if the mechanical load exceeds the rated load (maybe due to poor lubrication) or because it is being run on an excessive voltage (in that case it would overheat even on no-load) or because of an internal fault such as a breakdown in insulation in one of the windings.