Kw can be calculated from volts be using the formula
p=(voltage)square/resistance*1000
Use the following equation, kW = Amps x Volts x 1.73 x pf/1000.
The formula you are looking for is W = I x E. Watts = Amps x Volts divided by 1000.
1.44 kw
Volts and Kilowatts are different. no comparison can be drawn in respect to a straight conversion.
110 volts divided by 1,300 watts(1.3 kw) = .09 kw or 900 watts.
Use the following equation, kW = Amps x Volts x 1.73 x pf/1000.
To calculate the amperage, use the formula: Amperes = Watts / Volts. In this case, 55 kW is 55,000 watts. So, Amperes = 55,000 watts / 460 volts ≈ 119.57 amps.
The formula you are looking for is W = I x E. Watts = Amps x Volts divided by 1000.
Not enough information. You didn't specify the amount of kW - and you really can't calculate that, just from the volts. Once you know the amount of kW (which is a unit of power), you still need to multiply by time to get energy. Then you can do the appropriate conversion to BTU, which is also an energy unit.
For a single phase supply: you need to know the volts, kW and the power factor. If the power factor is unknown, assume 0.75, except for heating elements which have a power factor of 1. Multiply the kW number by 1000 then divide by the voltage. The answer should be divided by the power factor to find the current in amps.
To calculate the amperage, you can use the formula: Amperes = Watts / Volts. So, for a 500 kW system at 240 volts, the amperage would be 2083.33 Amps.
1.44 kw
Volts and Kilowatts are different. no comparison can be drawn in respect to a straight conversion.
To calculate the amperage current, you can use the formula: Amperes = Watts / Volts. In this case, it would be 10,000 Watts (10 KW) / 220 Volts = 45.45 Amperes. Therefore, the central air conditioner would use approximately 45.45 Amperes while running.
If the power output remains constant at 305 kW, doubling the voltage from 240V to 480V will halve the current drawn by the system. This change in voltage will not change the power output; it will remain at 305 kW.
The formula you are looking for is Amps = kW x 1000/1.73 x Volts x pf. The pf (power factor) of resistance heating will be 1. If the cooker was rated in kVA the same formula would be used minus the pf.
I (current in Amps) = E (volts) / R (resistance in ohms) ... W (Watts) = I x E ... The k simply means 1000