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mg+ 2e
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
uh2
You could draw it using Lewis structures, where valence electrons are represented by dots. You can also express it in equation form. The first ionization of calcium, for instance, could be expressed as: Ca --> Ca+ + e- As you can see, neutral calcium loses an electron to form the calcium +1 cation. Of course, we know that calcium will lose another electron as well, which can be expressed in the equation for the second ionization of calcium: Ca+ --> Ca++ + e- Normally, calcium will not experience a third ionization, because with two valence electrons, it has now achieved a full octet and is isoelectronic with argon.
ionization potential energy. but remember the atom must be neutral .
mg+ 2e
M + ionization energy à M1+ + e- M + ionization energy à M1+ + e-
Hg(g) -> Hg^+(g) + e^-
CH3CH2NH2+H2O⇌CH3CH2NH3++OH−
uh2
a=b=c
HClO. The Ionization Equation is H+ + ClO-
The equation for first ionization energy is the equation for the energy required to remove an electron from one mole of gaseous atoms to produce a mole of gaseous ions. It is as follows: X(g) ---> X^+1(g) + e^-1.
Mg + Ionization energy ----> Mg2+ + 2e
By all means. If an atom is neutral, then it has no need to attract or repel other atoms. But if it becomes positively or negatively charged (by taking away or adding one electron (btw: negative ionization is healthy)) then it will naturally attract it's opposite and attach to closest possible match.
The equation for the ionization of hydrochloric acid is as follows: HCl(aq) + H2O(l) --> H3O+(aq) + Cl-(aq) Note that 'free' protons, H+, do not exist in aqueous solution, and thus it is more proper to illustrate the proton transfer to water, instead of simply dissociating the acid into ions.
Lithium ====> Li , Electronic configuration { 1S2 2S1 } So we have only first ionization An the second will be from Complete stable energy level that need great amount of energy to remove it And that is impossible