Want this question answered?
The products will be potassium sulfate and water.
i think either potassium(II) sulfate or potassium sulfate
2KOH + H2SO4 -> 2H2O + K2SO4
BaCl2+K2SO4=2KCl+BaSO4
first things first, i don't think KH(SO4)k(OH) with K(SO4)H2O is a real balancing chemical equation.
The products will be potassium sulfate and water.
i think either potassium(II) sulfate or potassium sulfate
K2SO4 + 2NaOH ==> Na2SO4 + 2KOH
2KOH + H2SO4 -> 2H2O + K2SO4
Potassium has a low ionization energy.
BaCl2+K2SO4=2KCl+BaSO4
first things first, i don't think KH(SO4)k(OH) with K(SO4)H2O is a real balancing chemical equation.
potassium is greater in the second ionization energy.
2Fe(SO4)3 + 6KOH ---> 2Fe(OH)3 + 3K2(SO4) iron 3 is +3, sulfate is -2, potasium is +1, and hydroxide is -1
No. Potassium sulfate is a salt. It is weakly alkaline.
25
Assuming you mean a reaction between potassium (K) and copper(II) sulfate, your products would be potassium sulfate and copper in a single replacement reaction. Here's the equation:2K + CuSO4 --> K2SO4 + Cu