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What is the length of the diagonal of a rectangle whose width is five centimeters and whose length is twelve centimeters?
Wiki User
∙ 11y ago
This is solved by pythagoras theorem: The longest length of a right angled triangle is equal to the square root of the sum of the other lengths squared.
Therefore, 52 is 25, + 122 which is 144 = 169. The square root of 169 if i remember correctly is 13.
So 13cm
Wiki User
∙ 11y ago
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What is the area of a rectangle with width of twelve feet?
Its area is 12 square feet for every one foot of length.
What is the the answer to a rectangle area that is twelve feet wide and ten feet long?
A=w*l The area (A) of a rectangle equals the width (w) times the length (l) -- assuming both are measured with the same units. In this case, we substitute and get A=12 * 7.
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Simple. What you do get a ruler and something to get the angles matching up, therefore use the ruler to make a line 12 cm long. get the protracter and get the angles to match up.
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The length of a rectangle is 7 feet more than width if the length were decreased by 3 feet and the width were increased by 2 feet the perimeter would be 32 feet what is the length of the original re?
twelve -------------------- The original rectangle is 12 feet in length and 5 feet in width. The length (12) is 7 feet greater than the width (5 feet). Were the length decreased by 3 (12 - 3 = 9) and the width increased by 2 (5 + 2 = 7), the perimeter would be 32 feet (9 + 7 + 9 + 7 = 32).
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twelve
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100 cm in a meter 1200
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