0
What is the likelihood that the children of a woman heterozygous for colorblindness and a man with normal color vision will be colorblind?
Wiki User
∙ 7y ago
50/50 because the child gets 26 chromozones from each parent so the chances are 50/50.
Jody Fay
Wiki User
∙ 13y ago50 % chance
Xa
Y
XA
XAXa
XAY
Xa
XAXa
XaY
Add your answer:
Earn +20 pts
Is colorblind a sex linked trait?
Why is colorblindness a sex-linked trait? Descendants of colorblind hemophiliac man both disease are sex- linked? why do non of the children have either hemophila or colorblind
Since the colorblindness is located on the X chromosome colorblindness?
Why is colorblindness a sex-linked trait? Descendants of colorblind hemophiliac man both disease are sex- linked? why do non of the children have either hemophila or colorblind
If a color blind male who has normal clotting blood marries a female who is a carrier of hemophilia and has normal color vision could they have a color blind child?
In short, hemophilia has nothing to do with colorblindness, but YES, they could have a colorblind child if she is a carrier for the colorblindness gene. Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Any of her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy). So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
What would be the color vision of children if their mom is colorblind and their dad is normal?
Colorblindness is a recessive, sex-linked trait, and the gene that causes it occurs on the X chromosome. For the mother to be colorblind, she must have two copies of the gene and be homozygous recessive. The father, on the other hand, can not have the gene, because he (as a male) only has one X chromosome. So, if we let Xc represent the recessive gene for colorblindness and Xn represent the normal gene, the the mother is XcXc and the father is XnY. All of their children will receive the recessive gene from their mother. In the males, this means that they will be colorblind, because the chromosome they get from their father will by the Y chromosome. The daughters, however, will get the Xn gene, which is dominant and will override the gene for colorblindness. Thus, all of the couple's sons will be colorblind, and none of their daughters will be.
What is the genotype of a carrier of recessive disorder?
A carrier is someone who does not have a disorder but carries the allele on to offspring.
What are the chances of a male with normal vision and a color-blind female having a color blind son?
Color blindness is an X-linked trait. That means it is carried in the X chromosome, which differentiates whether a baby will be a girl or a boy. Women have two X chromosomes (XX), and men have an XY combination. If a woman is a carrier for color blindness, only one of her chromosomes will be affected (we'll call it a little "x"), and for that reason she will not be colorblind. Men, on the other hand, only have one X chromosome, so any time they carry the colorblindness gene, they will be colorblind. A woman will carry the colorblindness gene if: a. Her father is colorblind b. Her offpsring are colorblind She may carry the colorblindness gene if: a. Male family members (brothers, uncles, etc.) are colorblind A child inherits one chromosome from each parent. He/She will get an X chromosome from his/her mother, and an X from her father (if a girl) or a Y from his father (if a boy) So, If a woman has normal vision (assuming she does not have a family history of colorblindness), XX, and a man is colorblind, xY, they have several different chances for different offspring: Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) Xx (a normal girl who carries the colorblindness gene) XY (a normal boy) The short answer is that ALL CHILDREN WILL HAVE NORMAL VISION. However, all daughters will be CARRIERS, meaning they can pass colorblindness on to their children.
Colorblind male not colorblind female can there kid be color blind?
He will always be colorblind in that case because the defective gene is carried on the "X" chromosome, which males only have one of. You see, the colorblindness gene is recessive, which means if it is paired with a regular color seeing gene it is hidden, and the person can still see the difference between red and green. Because males have only one "X" chromosome, if they get the colorblindness gene from their mother, it will always lead to colorblindness. Side note: Males cannot receive the colorblindness gene from their Father, as he cannot give a "X" chromosome to his son. If he did, his son would be a daughter.
If a color blind man has a color blind daughter then the mother has to be color blind as well?
The father has to be colorblind for the daughter to be colorblind because both X chromosomes must have the colorblindness gene in females because the colorblind gene is recessive. If only the mother is color deficient, then she merely passes on the gene to one of the X chromosomes in a female. If both the mother and father are both colorblind, then both X chromosomes in the female are effected and the female is colorblind. There are two scenarios in which a daughter may be born colorblind. 1. The father is colorblind and the mother is a carrier of the colorblind gene. The daughter will be either colorblind or a carrier of the colorblind gene. 2. The father and mother are both colorblind. If this is the case, then all of the children will be born colorblind.
A womens father is colorblind She marries a colorblind man Will there son or daughter be colorblind?
Colorblindness is an X-linked recessive disorder. This means girls (who have the sex chromosomes XX) must have a colorblind X from dad and a colorblind X from mom. Boys only need to have one colorblind X to be colorblind because they have sex chromosomes XY (and have only 1 X). If the dad has it, he has the colorblind X. If the daughter has it, she must have gotten her mom's colorblind X. If the mom is colorblind, then every child they have will be colorblind. If the mom is not colorblind, then she must be a carrier - she must have 1 normal X and 1 colorblind X. Mom is either colorblind (with 2 colorblind Xs) or she is a carrier. Dad is definitely colorblind.
If children with blood group O and a what could be the blood group of parents?
both parents could be A heterozygous or one A heterozygous and the other O
If a color blind woman marries a man with normal vision the children will be?
there is a 50% chance that the child will be colorblind. If it is a boy, it will be colorblind, but if it is a girl, it will only be a carrier. Mother's chromosome is XrXr and Father's Chromosome is XRY, which means the children's genotypes will be XRXr if girl and XrY if a boy.
Will parents with a positive blood type have children with a positive blood type?
There is 50% that children will be of negative blood type if parents are heterozygous positive. 25% if one parent is homozygous and other heterozygous. 0% if both homozygous.
