90/3=30ma
The no-load current of a motor, such as a 90 kW motor operating at 440V and 60Hz, can vary based on its design and efficiency. Typically, the no-load current for such motors ranges from 10% to 30% of the full-load current. To estimate the no-load current, you can use the formula: No-load current ≈ Full load current × (no-load current percentage). The full-load current can be calculated using the formula: Full Load Current (A) = Power (W) / (Voltage (V) × √3 × Power Factor).
The current flowing through a transformer's secondary is the current drawn by the load, so it will be exactly the same as the current flowing through your induction motor -assuming that is the load. Don't really understand the point of your question!
The ratio is between 30% to 40 %
starting current of 3 phase 75 KW induction motor
1. Induction Motor has an air-gap but transformer has no air gap rather it is mutually link. 2. Induction Motor has high no-load current than transformer. 3. Induction Motor is a dynamic device. 4. Induction Motor has high power factor.
The slip is proportional to the load torque in an induction motor. This can also be seen as a reduction in speed causing extra current to be induced in the rotor to supply the increased torque.
whenever the load increases,the current drawn by the motor to do or to fulfill the required energy to the load. so the current will increase generally.Increase in load will cause the full utilization of motor,so speed of rotor will decrease.
due to high reluctance air gap magnetisation current is very high as a result no load current is more
yes
rotor speed will decrease....the rotor current wil increase.....
rotor speed will decrease....the rotor current wil increase.....
Induction motors are designed for a certain power. If the power demand is lower than that, you still have to setup the magnetic fields as if you were going to supply that maximum power. As a result, the no-load power factor of an induction motor is quite small, i.e. poor.