starting current of 3 phase 75 KW induction motor
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
whenever the load increases,the current drawn by the motor to do or to fulfill the required energy to the load. so the current will increase generally.Increase in load will cause the full utilization of motor,so speed of rotor will decrease.
If a DC series motor is started without load, the armature winding (winding that doesn't spin) current will be at a minimum, resulting in the motor going to maximum speed / runaway, which can cause things to fly apart. As Armature current increases, the speed of the motor will decrease. The armature current will be forced to increase / speed of the motor will be forced to decrease as more and more load is applied.
since torque is proportional to flux and armature current . Flux for dc shunt is constant . torque is proportional to armature current only. And initially armature current is very low hence it cannot be started at load .
The only time a motor should go into a locked rotor condition is if the motors connected load jams causing the motor to stop turning. At this point if the motor control circuitry is sized to the motor's full load amperage, the high rise in current will trip the motor off line.
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
As the no load current is the current due to core losses of the motor which is very small .in no load terminals are open circuited no current flows through it, a small current flows which is due to core
The start up current should be listed on the motor nameplate as FLA , full load amps.
whenever the load increases,the current drawn by the motor to do or to fulfill the required energy to the load. so the current will increase generally.Increase in load will cause the full utilization of motor,so speed of rotor will decrease.
This is a good indication that the motor is being overloaded. If the motor load is belt driven, remove the belt and then check the motor amps. If it goes back to normal FLA then there is a problem with the driven load. If the motor amperage stays high check the motor bearings for the problem.
The ratio is between 30% to 40 %
If a DC series motor is started without load, the armature winding (winding that doesn't spin) current will be at a minimum, resulting in the motor going to maximum speed / runaway, which can cause things to fly apart. As Armature current increases, the speed of the motor will decrease. The armature current will be forced to increase / speed of the motor will be forced to decrease as more and more load is applied.
since torque is proportional to flux and armature current . Flux for dc shunt is constant . torque is proportional to armature current only. And initially armature current is very low hence it cannot be started at load .
Across the line starting of a motor can be as high as 300% of the full load amps.
The current flowing through a transformer's secondary is the current drawn by the load, so it will be exactly the same as the current flowing through your induction motor -assuming that is the load. Don't really understand the point of your question!
The FLA of a motor is the amperage that the motor operates at. So to answer the question, 100%.
Too much load, or too weak of a supply. When a motor is initially started, it will pull a higher than normal amount of current. A sag may occur if the supply is too small, and then it should rebound after a short period of time. If the voltage stays low, either the supply is well undersized, or the motor is pulling more current than it should (either the load is too heavy for the motor or the motor is damaged or dirty).