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It is the value for the affinity for a fatty or water phase. It is the ratio of the amount of compound in the octanol:water phase. It is also called LogPOW or LogPO:W.
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∙ 14y ago
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What lop P value should drugs have for percutaneous administration?
They should have a log P value of 2.6.
How would you work out a percentage of depreciation for example if something cost 5500 pounds new then 9 years later it costs 2047.08 pounds what formula could you use?
Hold on to your hat! Suppose the rate of depreciation is p percent per year. Current value = Start Value*(1 - percentage/100)years That gives 2047.08 = 5500*(1 - p/100)9 So 0.3722 = (1 - p/100)9 or log(0.3722) = 9*log(1-p/100) -0.4292 = 9*log(1-p/100) -0.0477 = log(1-p/100) 10-0.0477 = 1-p/100 0.8960 = 1-p/100 p/100 = 1 - 0.8960 = 0.1040 and, finally, p = 0.1040*100 = 10.4%
How do you find when a number is reached due to a percentage of growth?
Suppose you have a variable which grows at r% per period [year] and you want to find out how many periods, t, it will take before it grows, from a starting value of P to reach the value Q.The approximate method used by younger pupils is trial and error. This is because the y do not have the necessary mathematical knowledge.After t periods, the variable in question will have increased from P to Q whereQ = P*(1+r/100)tthen Q/P = (1+r/100)ttaking logarithms, log(Q/P) = log[(1+r/100)t] = t*log(1+r/100)and so finally, t = log(Q/P) / log(1+r/100).
Can you multiply two irrational logarithms to get a rational answer?
Yes. Take any rational number p. Let a = any number that is not a power of 10, so that log(a) is irrational. and let b = p/log(a). log(a) is irrational so 1/log(a) must be irrational. That is, both log(a) and log(b) are irrational. But log(a)*log(b) = log(a)*[p/log(a)] = p which is rational. In the above case all logs are to base 10, but any other base can be used.
What is the value of log o?
The value of log o is penis
How can you find value of logarithm from log table?
determination of log table value
What annual rate of interest is required to triple an investment in 12 years?
If it is compounded annually, then: F = P*(1 + i)^t {F is final value, P is present value, and i is interest rate, t is time}.So if it triples, F/P = 3, and 12 years: t = 12, so we have 3 = (1 + i)^12, solve for i using logarithms (any base log will do, but I'll use base 10):log(3) = log((1+i)^12) = 12*log(1+i)(log(3))/12 = log(1+i).Now take 10 raised to both sides: 10^((log(3))/12) = 10^log(1+i) = 1 + ii = 10^((log(3))/12) - 1 = 0.095873So a rate of 9.5873 % (compounded annually) will triple the investment in 12 years.
What is the value of log 21.4?
log(21.4) = 1.330413773
What is the value of log 500?
log 500 = 2.69897
What is value of log 22?
log(22) = 1.342422681
What is the log value of 99 percent?
log(0.99) = -0.004364805
What is the numeric value of log?
The numeric value of log(x) is the power you have to raise 10 to in order to get 'x'.
