.01 M
10-4
dick
150 mL of a 2.5 M lidocaine solution contain 87,9 g.
1.5M * 50mL / 0.4M = 187.5 mL = 190 mL
Will a 0.5 M solution have a higher freezing point than a 0.75 M solution of the same substance?
The answer is 5 m L sodium bicarbonate, 1 M solution.
A solution of NaCl 1 M.
Slowly pour the 5 M acid into the water
HF has a higher [OH-] than a solution of 1.0 M HCl.
8.0*10^-10 m
25ml of the 4M stock solution used
(Volume)(1.00 M) = (75.0 ml)(12 M) (Volume)(1.00 M) = (900) Volume = 900 ml -----------------------
0.75 M
i have no freaking idea.
.01 M
25