A 25 millimole (m mol) solution means there are 25 millimoles of solute in every liter of solution. It is a unit used to express the concentration of a solute in a solution.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
The Molarity is equal to the number of moles divided by the liters. M=mol/L M=0.120 mol/5.0 L M=0.024 so the molarity is 0.024 M
0.751 mol/0.951 L = 0.790 mol/liter = 0.790 M
The molarity of the solution is calculated by dividing the moles of solute (0.250 mol NaCl) by the liters of solution (2.25 L). Molarity = moles of solute / liters of solution Molarity = 0.250 mol / 2.25 L = 0.111 M
25g HCl 1 mol 36.46g HCl =.686 mol M=.686 mol/1.5 L=.457M pH= -log(.457) pH= .34
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
You would need to measure 400 mL of the 0.250 M NaCl solution to obtain 0.100 mol of NaCl. This is calculated by dividing the amount of moles needed by the concentration of the solution: 0.100 mol / 0.250 mol/L = 0.400 L = 400 mL.
Molarity (M) = moles of solute (mol) / liter of solution (L)M = mol / LYou have 250 mL of Solution, which is250 mL x ( 1 L / 1000 mL ) = ( 250 / 1000 ) L = .25 LSolute is just what's dissolvedSolvent is just what it's being dissolved inSolution is the solute and the solvent.M = mol / LM = 0.65 mol / 0.25 Liters = 2.6 mol/LThe two numbers that you are given, 0.65 moles and 250 mL both have two significant figures, and the answer is two significant figures (2.6 mol/L)Therefore the answer is 2.6 mol/L.
The Molarity is equal to the number of moles divided by the liters. M=mol/L M=0.120 mol/5.0 L M=0.024 so the molarity is 0.024 M
0.751 mol/0.951 L = 0.790 mol/liter = 0.790 M
0.5 Moles If you have a 0.25 M solution, you have 0.25 mol/dm3, or 0.25 moles in 1 L (0.25 mol/L) If you have 2 L of solution, you have 2 L x 0.25 mol/L = 0.5 mol The L's cancel out, and you're left with moles.
1.52 mol/L * 1.00 L = 1.52 mol
25
The molarity of the solution is 1.0 M. This is calculated by dividing the number of moles of solute (0.5 mol Cu(NO3)2) by the volume of the solution in liters (0.5 L).
molarity = moles/litre [solution] = 12 mol/6 L [solution] = 2 mol/L = 2 M
Given: 0.5 g NaCl; 0.05 L of solution.1) Find the molar mass of NaCl.(22.99) + (35.45) = 58.44 g/mol of NaCl2) Convert grams of NaCl to moles of NaCl.(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl3) Use the molarity equation, M = mol / L, to solve for molarity (M).(0.00855578 mol NaCl / 0.05 L) = 0.17 M