Given: 0.5 g NaCl; 0.05 L of solution.
1) Find the molar mass of NaCl.
(22.99) + (35.45) = 58.44 g/mol of NaCl
2) Convert grams of NaCl to moles of NaCl.
(0.5 g NaCl) X (1 mol NaCl / 58.44 g NaCl) = 0.00855578 mol NaCl
3) Use the molarity equation, M = mol / L, to solve for molarity (M).
(0.00855578 mol NaCl / 0.05 L) = 0.17 M
1.3g
2.0 mol NaCl / 2.0 Litre = 2.0/2.0 = 1.0 mol/L = 1.0M NaCl
This molarity is 0,618.
The molecular weight of NaCl is 58.443 g/mol. 78/58.443 is 1.300412367606 moles. It is in litres so it is 1.300412367606 molar.
Molarity: The number of moles of solute dissolved per litre of solution. it is simply a concentration which can be measured easily. 1)Take known amount of solution of water (say 5 litre) 2)Take solute(NaCl) of known amount(say 1500 gm) 3)Add the solute in the water top make the solution. Apply the formula Molarity=(Mass of solute)/Molecular5 mass of NaCl/litre of solution for more inf cont (fahim.ch01@gmail.com) Molarity= Moles of Solute/Liters of Solution
4m
Dissolve 116,879 g of pure NaCl in 1 L demineralized water at 20 0C.
What is the molarity of a solution that has 50 grams of KOH dissolved in enough water to make 800 mL of solution?
Because you have 6.68 moles of Li2SO4 and 2.500 liters of water, the overall molarity of your solution is 2.67 M.
when any ionizable cpmpound is dissolved in water it becomes an electrolytic solution as NaCl or HCl in water....
0.0004 M
0.5