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This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.
Known/Given:
volume of acetone= 28.62mL
density of acetone at 25oC = 0.791g/mL
Unknown:
mass of acetone
Formula:
density = mass/volume
Solve for mass:
density x volume = mass
0.791g/mL x 28.62mL = 22.6g
Wiki User
∙ 9y ago
To find the mass of acetone, you need to know its density. The density of acetone is 0.79 g/mL. Multiply the volume (28.62 mL) by the density to get the mass in grams. Mass = Volume x Density = 28.62 mL x 0.79 g/mL = 22.58 grams.
Wiki User
∙ 10y ago22.39g acetone has a density of 0.7857g/cm^3 which is the same as saying 0.7857g/mL/ Multiply for mass: 0.7857*28.50=22.39g (mL gets cancelled out)
Wiki User
∙ 11y agoDensity of acetone = 0.791 gm/mL
(0.791 gm/mL) x (17.53 mL) = 13.866 grams
Wiki User
∙ 13y ago28,5 mL (volume) x 0,7925 g/cm3 (density) = 22,586 g (mass)
jaremesha randle
What is the mass in grams of 33.30 mL of acetone?
Wiki User
∙ 9y agoThe mass is 22,72 g.
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What is the mass in grams of 28.40mL of acetone?
To find the mass of acetone, we need to know the density of acetone, which is 0.786 g/mL. Multiplying the volume (28.40 mL) by the density gives us the mass of acetone: 28.40 mL * 0.786 g/mL = 22.33 grams.
What is the mass in grams of 38.86 of acetone?
To find the mass of 38.86 moles of acetone, you need to multiply the number of moles by the molar mass of acetone, which is approximately 58.08 g/mol. Therefore, the mass of 38.86 moles of acetone is approximately 2261.11 grams.
What is the acetone concentration in ppm of a solution made by mixing 23.2 mg acetone with 2.000 L water?
To calculate the concentration of acetone in ppm (parts per million), you would first convert the mass of acetone to grams (23.2 mg = 0.0232 g). Then you would divide the mass of acetone by the total mass of the solution (0.0232 g acetone / 2000 g water) and multiply by 1,000,000 to convert to ppm. Therefore, the acetone concentration would be 11.6 ppm.
What is the percent by mass of carbon in aceton C3H6O?
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
What is the molar mass of fingernail polish remover?
The molar mass of fingernail polish remover, which is typically acetone (CH3COCH3), is approximately 58 grams per mole.
What is the mass in grams of 17.54mL of acetone?
With a density of 0.7857g/cm3, you have a mass of 13.78mL.
What is the mass in grams of 38.86 of acetone?
To find the mass of 38.86 moles of acetone, you need to multiply the number of moles by the molar mass of acetone, which is approximately 58.08 g/mol. Therefore, the mass of 38.86 moles of acetone is approximately 2261.11 grams.
What is the Volume of 10 grams of acetone?
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
What is the acetone concentration in ppm of a solution made by mixing 23.2 mg acetone with 2.000 L water?
To calculate the concentration of acetone in ppm (parts per million), you would first convert the mass of acetone to grams (23.2 mg = 0.0232 g). Then you would divide the mass of acetone by the total mass of the solution (0.0232 g acetone / 2000 g water) and multiply by 1,000,000 to convert to ppm. Therefore, the acetone concentration would be 11.6 ppm.
What is the volume in ml of 6.54 g of acetone?
To find the volume of a substance, you would need to know its density. The density of acetone is approximately 0.79 g/mL. Using this information, you can calculate the volume of 6.54 g of acetone by dividing the mass by the density (6.54 g / 0.79 g/mL = 8.27 mL).
What is the percent by mass of carbon in aceton C3H6O?
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
The mass of 12 cc's of acetone is?
The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g
What is the percent of acetone c3h6o?
Acetone (C3H6O) is composed of 63.64% carbon, 13.64% hydrogen, and 22.73% oxygen by mass.
If the mass of the container is 14.5 grams what is the mass of the sand?
To determine the mass of the sand, you'll need to subtract the mass of the container (14.5 grams) from the total mass of the container with sand in it. For example, if the total mass of the container with sand is 50 grams, then the mass of the sand would be 50 grams - 14.5 grams = 35.5 grams.
How many grams are in mass?
Grams are a measure of mass.
What is percent by mass of carbon in acetone C3H6O?
To calculate the percent by mass of carbon in acetone (C3H6O), first calculate the molar mass of carbon in acetone: 3(C) = 3(12.01 g/mol) = 36.03 g/mol. Then calculate the molar mass of acetone: (3(12.01 g/mol) + 6(1.01 g/mol) + 16.00 g/mol = 58.08 g/mol. Finally, divide the molar mass of carbon by the molar mass of acetone and multiply by 100 to get the percent by mass of carbon in acetone: (36.03 g/mol / 58.08 g/mol) x 100 ≈ 62.07%.
What is the mass of the container if the net mass is 75 grams and the gross mass is 80 grams?
80 - 75 = 5 grams.
