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Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.Known/Given:volume of acetone= 28.62mLdensity of acetone at 25oC = 0.791g/mLUnknown:mass of acetoneFormula:density = mass/volumeSolve for mass:density x volume = mass0.791g/mL x 28.62mL = 22.6g
What is the volume, In millimeter of 6.68 g of acetone ?
the answer is 6.3%
molacular mass
With a density of 0.7857g/cm3, you have a mass of 13.78mL.
Acetone has the molecular formula of CH3COCH3 (C3H6O) and a molar mass of 58.08 g/mol.
To find the volume of 10 grams of acetone, you use the fact that the density of acetone is 0.7857 grams per cubic centimeter. The density formula is given as mass divided by volume, or m/V. The volume is mass/density or 10/0.7857, which is equal to 12.73 cubic centimeter.
This is a density problem. Density = mass/volume. As long as we know two of the variables, we can solve for the missing variable. The density of acetone is 0.791g/mL at 25ºC.Known/Given:volume of acetone= 28.62mLdensity of acetone at 25oC = 0.791g/mLUnknown:mass of acetoneFormula:density = mass/volumeSolve for mass:density x volume = mass0.791g/mL x 28.62mL = 22.6g
What is the volume, In millimeter of 6.68 g of acetone ?
The density acetone is 0.79 g/cm3. So 12 cm3 has a mass of 9.48 g
Grams are a measure of mass.
the answer is 6.3%
153 grams
80 - 75 = 5 grams.
molar mass divided by atomic mass times 6.02 x 1023 =)
This mass is 5,323 grams.