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Magnesium has the molar mass of 24.305 grams per mole. 0.229 moles of Mg has a mass of about 5.57 grams.
Wiki User
∙ 9y ago
Wiki User
∙ 14y agoNo. of mol = mass/Ar (Atomic radius)
As such, mass = no. of mol multiplied by Ar
To answer your question,
Mass of 0.018 mol Mg = 0.018 X 24.3 = 0.437 (rounded up to 3 sig. fig)
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What is the molar mass of MgS?
The molar mass of Mg = 24.305 g/mol
When 4.00g of magnesium burns the theoretical yield of magnesium oxide is?
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide
3 atoms of magnesium combine with 2 atoms of nitrogen.What will be the weight of magnesium which combines with 1.86g of nitrogen?
Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.
What is the mass of magnesium oxide when you burn 4 grams of magnesium?
Mg grams -> (use Mg's molar mass) -> Mg moles -> (use ratio of moles - use balanced equation) -> MgO moles -> (use MgO's molar mass) -> grams MgO set up the equation: Mg + O2 --> MgO (we know the product is MgO and not MgO2 because magnesium has a charge of 2+ while oxygen has a charge or 2-) balance the equation: 2Mg + O2 --> 2MgO Molar mass of Mg: 24.31 g/mol Molar mass of MgO: 44.30 g/mol (add the molar mass of Magnesium - 24.31g/mol and the molar mass of Oxygen - 15.99g/mol together) (use periodic table to find these) 7.0 grams of Mg To find the moles of Magnesium you use the molar mass of Mg. (7.0 g Mg)*(1 mol Mg / 24.31 g Mg) =0.2879 moles Mg notice how the grams cancel to leave you with moles - remember dividing by a fraction is the same as multiplying by the reciprocal Now use the balanced equation's coefficients and the moles of Mg to determine the number of moles of MgO present. 2Mg + O2 --> 2MgO 2 moles Mg : 2 moles MgO -> divide both sides by 2 and it obviously becomes a 'one to one' ratio. This means that the number of moles of Mg is equal to the number of moles of MgO. This means that there are 0.2879 moles of MgO. Now that we know MgO's molar mass and the number of moles of MgO we have, the grams of MgO produced can be determined. (0.2879 moles MgO)*(44.30 g MgO / 1 mol MgO) = 12.75 grams MgO
What is the mass of a sample containing 5.82 mol of zinc?
378.3g You multiply the RMM by the Concentration (mol) Mass(g)=Concentration(mol)*RMM
Mass of 3.65 mol Mg?
To solve this first the molar mass of Mg is needed (look at a periodic table). (Mg=23.0g/mol) Then convert the mols to grams as follows: (3.65 mol Mg) x (23.0 g/mol Mg) = 84.0 g Mg The mol units cancel in the conversion leaving only the gram units and the ammount in grams.
What is the molar mass of mg o?
The molar mass of Mg O = 40.3044 g/mol
What is the molar mass of MgS?
The molar mass of Mg = 24.305 g/mol
What is the formula mass of magnesium nitrite octahydrate?
Mg(NO3)2Mg = 24.312N = 28.026O = 96.00_________+Mol=148.33 g/mol
What is the formula mass of magnesium perchlorate?
Mg(ClO4)2 with molar mass 223.206 g/mol
When 4.00g of magnesium burns the theoretical yield of magnesium oxide is?
2 Mg (s) + O2 (g) → 2 MgO (s)4.00mg x 1 mol Mg/24.305 x 2 mol MgO/2 mol Mg x 40.305g MgO/1 mol MgO==6.63g4.00g- Given24.305g- Atomic Mass of Magnesium40.305g- Atomic Mass of Magnesium Oxide
How many milliliter is 80mg?
ml is a size for an amount of fluid. mg is a size for a mass. You can convert ml in mg if you know the material your dealing with. Then you need the periodic system of elements and calculate the molecular weight of you material knowing; mol(n) = mass(mg) / molecular weight(g) then calculate the volume (ml) =mol(n) / concentration(c)
3 atoms of magnesium combine with 2 atoms of nitrogen.What will be the weight of magnesium which combines with 1.86g of nitrogen?
Equation: 3Mg + N2 → Mg3N2 3mol Mg combines with 1mol N2. Molar mass N2 = 28.014g/mol 1.86g N2 = 1.86/28.014 = 0.0664mol N2 This will require 0.0664*3 = 0.1992mol Mg Molar mass Mg = 24.305g/mol 0.1992mol Mg = 24.305*0.1992 = 4.84g Mg required.
Calculate the number of moles present in each of the following samples.6.684e13 pg of fluorine atoms 2.435e6 mg of magnesium 3.2e-3 kg of lead(II) chloride 6.684e-5 Mg of fluorine 2.31e-9 Gg of carbon disulfide 4.91e9 ng of aluminum sulfate?
umber of Moles= Molar Mass (in g/mol) Mass (in grams) First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample: 6.684e13 pg of fluorine atoms: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e13 pg = 6.684e-6 g Number of moles = (6.684e-6 g) / (19 g/mol) ≈ 3.52e-7 moles 2.435e6 mg of magnesium: Molar mass of magnesium (Mg) = 24.305 g/mol Mass in grams = 2.435e6 mg = 2.435 g Number of moles = (2.435 g) / (24.305 g/mol) ≈ 0.1001 moles 3.2e-3 kg of lead(II) chloride: Molar mass of lead(II) chloride (PbCl₂) = 207.2 g/mol Mass in grams = 3.2e-3 kg = 3200 g Number of moles = (3200 g) / (207.2 g/mol) ≈ 15.45 moles 6.684e-5 Mg of fluorine: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e-5 Mg = 6.684e-5 g Number of moles = (6.684e-5 g) / (19 g/mol) ≈ 3.52e-6 moles 2.31e-9 Gg of carbon disulfide: Molar mass of carbon disulfide (CS₂) = 76.143 g/mol Mass in grams = 2.31e-9 Gg = 2.31e15 g Number of moles = (2.31e15 g) / (76.143 g/mol) ≈ 3.03e12 moles 4.91e9 ng of aluminum sulfate: Molar mass of aluminum sulfate (Al₂(SO₄)₃) = 342.15 g/mol Mass in grams = 4.91e9 ng = 4.91e-6 g Number of moles = (4.91e-6 g) / (342.15 g/mol) ≈ 1.43e-8 moles
What mass of magnesium will react with 497.1 mL of oxygen at 157.6C and 0.959 ATM?
The balanced chemical reaction equation is2 Mg + O2 ----> 2 MgOIdeal gas law gives oxygen moles :n = PV/RT = ( 0.959 atm ) ( 0.4971 L )/ ( 0.08205 L - atm/mol - K ) ( 157.6 + 273.2 K )n = 0.01349 mole O2Two moles og Mg are needed for each mole of O2.moles Mg needed = ( 2 ) ( 0.01349 ) = 0.02697 moles MgMass of Mg = ( mols of Mg ) ( M of Mg )Mass of Mg = ( 0.02697 mol ) ( 24.31 g Mg/mol Mg ) = 65.57 grams of magnesium
How many grams of MgO are produced when 40 grams of 02 react with Mg?
:Mg: (2.43 g)/(24.3 g/mol) = .1 mol :MgO: (.1 mol)(24.3+16.0 g/mol) = 4.03 g
How many molecules of carbon tetrachloride are in 6.32 mg of that compound?
1. Convert 6.32 mg to grams.6.32 mg x 1g/1000 mg = 0.00632 g2. Determine the molar mass for CCl4.The molar mass is 153.82g/mol (Wikipedia)3. Convert given mass to moles using the molar mass.0.00632 g CCl4 x 1 mol CCl4/153.82 g CCl4 = 4.11 x 10^-5 mol CCl44. Convert moles to molecules.One mole of molecules is 6.022 x 10^23 molecules.4.11 x 10^-5 mol CCl4 x 6.022 x 10^23 molecules CCl4/mol CCl4 = 2.47 x 10^19 molecules CCl4
