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40.9882 g/mol
2.38 mol Al
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.00 moles Al × (27.0 grams) = 54.0 grams Al
The formular you need is M = n/m (molar mass = amount of substance/mass), or n = m/MAluminium has a molar mass of 26.982 g/mol. The given mass is 3 grams. Therefore:n(Al) = 3g / (26.982g/mol) = 0.11mol
To the nearest gram, molar mass of aluminium carbonate is 234 g/mol.
The mass of 7 050 moles of natural uranium is 238,02891 x 7 050.
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
The atomic mass of Aluminum Sulfide is 150.158 g/mol
40.9882 g/mol
Aluminum Oxide is Al2O3 and Al = 27 and oxygen =16 so the molar mass is 102 g/mol Al2O33.75 mol Al ~ 3.75/2 mol Al2O3 ~ (3.75/2)mol * 102 g/mol = 191.25 = 191 gram Al2O3
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
Molar Mass of Al: 2(27.0g/mol) = 54.0g/mol Molar Mass of O: 3(16.0g/mol) = 48.0g/mol Molar Mass of compound: 102.0g.mol (54.0g/mol / 102.0g/mol) x 100% = 52.9%
2.38 mol Al
The atomic mass of Aluminum Sulfide is 150.158 g/mol
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.00 moles Al × (27.0 grams) = 54.0 grams Al
Each compound has a different molar mass.
The formular you need is M = n/m (molar mass = amount of substance/mass), or n = m/MAluminium has a molar mass of 26.982 g/mol. The given mass is 3 grams. Therefore:n(Al) = 3g / (26.982g/mol) = 0.11mol