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Q: What is the mass of 1.0 mol of H2O?
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What is the gram formula mass for H2O?

H2O's molar mass is 18 g/mol.


What is the mass (in grams) of 1 mol H2O?

You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O


What is the molcular mass of water?

Molar mass of H2O = 18.01528 g/mol


What is the mass in grams of 5.00 x 10 to the 2nd power water molecules?

The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O


How many moles are there in 235 grams of H2O?

For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O


What is the molar mass of H2O to the nearest whole number?

18g/mol


How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?

19,5 g butane are needed.


The mass percent of water in a hydrate of mncl2 is 36.41 percent what is the fomular of the hydrate?

36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate


What is 1 mol of H2O in grams?

in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g


Find the mass in grams of 1.54 moles of H2O?

1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams


What is the value of x When a 1.63 g sample of MgCl2xH2O is heated to remove all water a mass of 0.762 g remains?

You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O


How many grams of water are produced by reacting 15.8 g H2 with excess oxygen?

24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O