You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
249.72 g/mol
1 mole H2O = 18.02g H2O 3.2mol H2O x 18.02g/mol = 58g (rounded to two significant figures)
First find the molar mass of water using the atomic mass of the elements that make up water (H2O) = (2x1.01g/mol+16g/mol) = 18.02 g/mol. Then we know 1mol water is 18.02g so we multiply 18.02g/mol H20 x 1.5mol H2O to get 27.03g but rounds to 27 because 1.5mols has two significant digits.
H2O's molar mass is 18 g/mol.
You calculate it by using Avogadro's number: 6.022 x10 23 which is one mole of substance. 1.00 x 1024 divided by 6.022 x 1023 = 10 divided by 6.022 = 1.661 mol H2O Use the molar mass of water (18.02 g mol-1) to get to the mass in grams. 18.02 g x 1.661 mol = 29.93 g H2O
Molar mass of H2O = 18.01528 g/mol
The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O=18.0 grams235 grams H2O / (18.0 grams) = 13.1 moles H2O
18g/mol
19,5 g butane are needed.
36.41% = .3641 g of H2O 63.59% = .6359 g of MnCl2 .6359g MnCl2 x (1molm MnCl2/125.84g MnCl2)=.0051 mol MnCl2 .3641g H2O x (1 mol H2O/ 18.02g H2O) = .0202 mol H2O .0051 mol MnCl2 / .0051 = 1mol MnCl2 .0202 mol H2O /.0051 = 3.96 = 4 mol H2O Formula is: MnCl2 4H2O Manganese (II) chloride tetrahydrate
in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g
1.54 moles H2O (18.016 grams/1 mol H2O ) =27.7 grams
You begin with 1.63 g of MgCl2•xH2O. You end up with 0.762 g MgCl2. That means you lost 1.63 - 0.762 = 0.87 g of H2O. 0.762 g MgCl2 / 95.21 g (molar mass) = .00800 mol MgCl2 0.87 g H2O / 18.02 g (molar mass) = .048 mol H2O x = mol solute / mol solvent x = .048 mol H2O / .00800 mol MgCl2 x = 6 MgCl2•6H2O
24g H2 x 1 mol H2 x 2 mol H2O x 18g H2O/ 2g H2 x 2 mol H20= 216 g H2O 160g O2 x 1 mol O2 x 2 mol H2O x 18g H2O/ 32g O2 x 1 mol O2 x 1 mol H2O= 180 g H2O