in order to find the mass of H20 you need the molar mass which is 18.01g/mol and to calculate the mass you just multiply by the number of moles. 18.01 * .20 = 3.60g
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
To find the number of moles in 48 grams of water, we first need to calculate the molar mass of water (H2O), which is approximately 18 grams/mol (1 mol of H2O = 18 grams). Then, we divide the given mass (48 grams) by the molar mass to get the number of moles. In this case, 48 grams / 18 grams/mol ≈ 2.67 moles of water.
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
To have 1 mole of H2O, you would need to weigh out approximately 18 grams of water (H2O). This is because 1 mole of water molecules (H2O) has a molar mass of about 18 grams/mol (2 grams/mol for hydrogen x 2 atoms + 16 grams/mol for oxygen).
To find the mass of 1.54 moles of H2O, you can use the molar mass of water. The molar mass of H2O is 18.015 grams/mol. Therefore, the mass of 1.54 moles of H2O would be 1.54 moles * 18.015 grams/mol = approximately 27.75 grams.
To find the grams of H2O and C3H6 formed from 6g of C3H8O, first calculate the molar mass of C3H8O: 44.1 g/mol. Then, using the stoichiometry of the reaction yielding H2O and C3H6 from C3H8O, you can determine the grams produced. The balanced reaction is C3H8O -> H2O + C3H6, and for every 1 mol of C3H8O, you get 1 mol of H2O and 1 mol of C3H6. So, 6g of C3H8O yields 6g of H2O and 6g of C3H6.
200 grams H2O (1 mole H2O/18.016 grams)(6.022 X 1023/1 mole H2O) = 6.69 X 1024 molecules of water ======================
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
The molarity is 0,41 mol/L.
To find the number of moles in 48 grams of water, we first need to calculate the molar mass of water (H2O), which is approximately 18 grams/mol (1 mol of H2O = 18 grams). Then, we divide the given mass (48 grams) by the molar mass to get the number of moles. In this case, 48 grams / 18 grams/mol ≈ 2.67 moles of water.
In 1 molecule of H2O, there are 2 atoms of H. Therefore, in 1 mol of H2O, there are 2 mol of H. So, in 4.51 mol of H2O, there would be 4.51 * 2 = 9.02 mol of H.
0.8 moles HNO3 (63.018 grams/1 mole HNO3) = 50 grams nitric acid ===============
N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams
2.2 mol water = 2.2 (mol) * 18 (g/mol) water = 39.6 (mol*g/mol) = 40 g18 g/mol = mol mass of H2O = 2*H + 1*O = (2*1 + 16) g/mol