N2O5 Has a molar mass of 108.01 g/mol
1.73 mol x 108.01 g/mol = 187 grams
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.
Dinitrogen tetroxide or nitrogen(IV) oxide
In order to answer this question you need to know the molar mass of dinitrogen trisulfide (N2S3), and that 1 mole of molecules is equal to 6.022 x 1023 molecules. Molar mass is determined by multiplying each element's subscript by that element's atomic weight on the periodic table, and expressing it in grams/mole.1 mole N2S3 molecules = 6.022 x 1023 molecules N2S3molar mass N2S3 = 124.208g/molConvert molecules to moles.2.26 x 1025 molecules N2S3 x (1mol N2S3/6.022 x 1023 molecules N2S3) = 37.5 moles N2S3Convert moles to mass in grams.37.5mol N2S3 x (124.208g N2S3/1mol N2S3) = *4660 grams N2S3*The answer is rounded to three significant figures.
Molar mass of N2O5 = (2x14.007) + (5x15.999) = 28.014 + 79.995 = 108.009 g/mole.
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
Dinitrogen tetroxide or nitrogen(IV) oxide
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
Yoy need to know the molar mass of this solute and the mass of the solute:moles = total mass/molar mass
You need to be more specific, there is more than one oxide of nitrogen specifically dinitrogen monoxide, nitric oxide, dinitrogen trioxide, nitrogen dioxide, dinitrogen tetroxide, dinitrogen pentoxide and nitrogen trioxide. A start can be made by measuring its density. A mass spectrometer would do it.
The molar mass is the sum of atomic weight of the atoms contained in a molecule. Example: water, H2O The molar mass is: 2 x 1,008 + 15,999 = 18,015 Molar mass is used in many calculus in chemistry.
44g