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To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.

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1y ago

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How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?

Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.


How many molar mass in g mol of dinitrogen pentoxide?

N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams


What is the name of Ni2O3?

N2O is the formula for nitrous oxide, popularly referred to as laughing gas. Its molar mass is 44.013 g/mol, and it is soluble in water.


What is the mass of 3.28 moles of dinitrogen tetroxide?

The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.


What is the mass of 1 molecule of dinitrogen?

44g


How many grams are there in a container of 2.26x1025 molecules of dinitrogen trisufide?

In order to answer this question you need to know the molar mass of dinitrogen trisulfide (N2S3), and that 1 mole of molecules is equal to 6.022 x 1023 molecules. Molar mass is determined by multiplying each element's subscript by that element's atomic weight on the periodic table, and expressing it in grams/mole.1 mole N2S3 molecules = 6.022 x 1023 molecules N2S3molar mass N2S3 = 124.208g/molConvert molecules to moles.2.26 x 1025 molecules N2S3 x (1mol N2S3/6.022 x 1023 molecules N2S3) = 37.5 moles N2S3Convert moles to mass in grams.37.5mol N2S3 x (124.208g N2S3/1mol N2S3) = *4660 grams N2S3*The answer is rounded to three significant figures.


How many molecules are present in 1296 g of dinitrogen pentoxide?

Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.


How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?

To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.


What is the molar mass for dinitrogen pentoxide N2O5?

Molar mass of N2O5 = (2x14.007) + (5x15.999) = 28.014 + 79.995 = 108.009 g/mole.


What is the chemical name for N2O4?

Dinitrogen tetroxide or nitrogen(IV) oxide


How much would two moles of dinitrogen pentoxide weigh?

The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g


Is molecules a force?

Molecules are not a force, they have mass.