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Molar mass of N2O5 = (2x14.007) + (5x15.999) = 28.014 + 79.995 = 108.009 g/mole.

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How much would two moles of dinitrogen pentoxide weigh?

The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g


How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?

To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.


How many molar mass in g mol of dinitrogen pentoxide?

N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams


How many molecules are present in 1296 g of dinitrogen pentoxide?

Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.


What is the mass of 3.97x1021 molecules dinitrogen tetraoxide?

To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.


How many MOLES of dinitrogen tetraoxide are present in 4.00 grams of this compound?

Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.


What is the chemical name for N2O4?

Dinitrogen tetroxide or nitrogen(IV) oxide


What is the mass of 3.28 moles of dinitrogen tetroxide?

The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.


What is the mass percentage of nitrogen in n2o5?

88


What is the test for nitrogen oxide?

You need to be more specific, there is more than one oxide of nitrogen specifically dinitrogen monoxide, nitric oxide, dinitrogen trioxide, nitrogen dioxide, dinitrogen tetroxide, dinitrogen pentoxide and nitrogen trioxide. A start can be made by measuring its density. A mass spectrometer would do it.


What is the mass of 1 molecule of dinitrogen?

44g


What is the molar mass of SiC?

Molar Mass of Carbon + Molar Mass of Silicon = Molar Mass of SiC. 12.0107 + 28.0855 = 40.0962 g / mol.