Molar mass of N2O5 = (2x14.007) + (5x15.999) = 28.014 + 79.995 = 108.009 g/mole.
You need to be more specific, there is more than one oxide of nitrogen specifically dinitrogen monoxide, nitric oxide, dinitrogen trioxide, nitrogen dioxide, dinitrogen tetroxide, dinitrogen pentoxide and nitrogen trioxide. A start can be made by measuring its density. A mass spectrometer would do it.
The molar mass of sulfur is 32.065. Molar mass is the mass per mole of a substance. In other words, Molar Mass = Mass/Amount of Substance.
to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu) to find molar mass you add the molar mass of the carbons 3(amu)+ molar mass of the hydrogens 8(amu)
Lithium has a molar mass of 6.94 g/mol. Oxygen has a molar mass of 16.00 g/mol. Since Lithium Oxide has 2 Lithium atoms, the molar mass is: (6.94 x 2) + 16.00 = 29.88 g/mol.
helium = 4 molar mass
The chemical formula of dinitrogen pentoxide is N2O5 . We can calculate its molar mass (mass of one mole) by multiplying the subscript of each element by its molar mass (atomic weight on the periodic table in grams/mole) and adding them together.Molar mass N2O5 =(2 x 14 g/mol N) + (5 x 16 g/mol O) = 108 g/mol N2O5The mass of two moles of N2O5 is (2 x 108 g/mol N2O5 ) = 216 g
To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.
N2O5 Has a molar mass of 108.01 g/mol 1.73 mol x 108.01 g/mol = 187 grams
Ar of N = 14g/mol Ar of O = 16g/mol Mr of N2O5 = 2(14)+5(16) = 108g/mol Using the formula : number of moles = mass / Mr number of moles = 1296g / 108g/mol = 12mol Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.
To calculate the mass of 3.97x10^21 molecules of dinitrogen tetraoxide, you first need to find the molar mass of dinitrogen tetraoxide (N2O4), which is about 92.02 g/mol. Then you can use Avogadro's number (6.022x10^23 molecules/mol) to convert molecules to moles and then multiply by the molar mass to find the mass.
Dinitrogen tetraoxide, or N2O4 has a molar mass of 92.011 grams per mole. This means there are 0.0435 moles present.
Dinitrogen tetroxide or nitrogen(IV) oxide
The mass of 3,28 moles of dinitrogen tetroxide is 301,8 g.
88
You need to be more specific, there is more than one oxide of nitrogen specifically dinitrogen monoxide, nitric oxide, dinitrogen trioxide, nitrogen dioxide, dinitrogen tetroxide, dinitrogen pentoxide and nitrogen trioxide. A start can be made by measuring its density. A mass spectrometer would do it.
44g
Molar Mass of Carbon + Molar Mass of Silicon = Molar Mass of SiC. 12.0107 + 28.0855 = 40.0962 g / mol.