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Ar of N = 14g/mol

Ar of O = 16g/mol

Mr of N2O5 = 2(14)+5(16) = 108g/mol

Using the formula : number of moles = mass / Mr

number of moles = 1296g / 108g/mol = 12mol

Each mole of substance contains 6.02 x 10^23 particles, therefore 1296g of N2O5 contains 12 x 6.02 x 10^23 = 7.224 x 10^24 molecules.

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How many molecules are present in 1296 g of dinitrogen pentoxide (N2O5)?

To find the number of molecules in 1296 g of dinitrogen pentoxide (N2O5), first calculate the molar mass of N2O5 which is 108 g/mol. Then, divide the given mass by the molar mass to get the number of moles (12 moles). Finally, use Avogadro's constant (6.022 x 10^23) to convert moles to molecules, giving approximately 7.2 x 10^23 molecules.


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