Well first things first you have to balance the equation
Fe3O4-->3Fe+2O2
Then because your given mass is in kg you have to convert it to grams
100.0kgx1,000kg/(over)1g=100,000g or 1.0x105
Next because you have mass of Fe3O4 you need to get the molar mass.
(3)55.85gFe+(4)16.00gO=231.55gFe3O4
Now convert grams to moles for your final answer
1.0x105gFe3O4x1mol/(over)231.55g(mm)x3molFe/(over)1mol Fe=1295.6 mol Fe
you can recover 1295.6moles of Fe from Fe3O4
If you follow the rule of Significant Figures, 100.0kg has 4 significant figures (digits) so your answer needs to have 4 digits
1295.6=1296
you can recover 1296 moles of Fe from Fe3O4
Fe3O4 is a compound. It is known as iron(II,III) oxide, where iron atoms are present in a combination of +2 and +3 oxidation states with oxygen.
the valance number of iron is 3 why,becouse in the formula after iron there is 3.the question ask you what is the valency of Fe3O4....
To calculate the amount of iron that can be recovered from FeO, we need to consider the molar ratio between Fe and FeO. FeO consists of 1 iron atom and 1 oxygen atom. The molar mass of Fe is 55.85 g/mol, and the molar mass of FeO is 71.85 g/mol. By dividing the molar mass of Fe by the molar mass of FeO and multiplying by the given mass of FeO, we can determine the amount of iron that can be recovered.
Yes, iron oxide can exist as a non-stoichiometric compound. This means that the ratio of iron to oxygen atoms in the compound is not a whole number and can vary. Examples include magnetite (Fe3O4) and wüstite (FeO).
Iron reacts with oxygen to form iron oxide. The chemical formula for iron oxide is Fe2O3 (rust) or Fe3O4.
The balanced chemical equation for the reaction between Fe3O4 and H2 is: Fe3O4 + 4H2 -> 3Fe + 4H2O From the equation, it can be seen that 1 mole of Fe3O4 reacts with 4 moles of H2. Calculate the moles of H2 in 300g, then use the mole ratio to find the moles of Fe3O4 needed. Finally, convert the moles of Fe3O4 to grams using its molar mass to determine the amount required.
Never. iron shows either +2 or +3 oxidation state but in Fe3O4 its oxidation state is seems to +4 but it is actually mixture of one moles FeO and one mole Fe2O3 , (FeO.Fe2O3 = Fe3O4).
91.6%
FeO, Fe2O3, Fe3O4 Note: Fe3O4 can be considered as a mixture of FeO and Fe2O3
If 85.65g of iron forms 118.37g of the oxide, the mass of oxygen combined with this mass of iron is 32.72g. Calculate the number of moles of iron and oxygen which have combined (after all, the formula of a compound shows the ratio of the number of moles of each element combined). Do this by dividing the mass reacted by the Relative Atomic Mass of the element concerned. i.e. For Iron it is 85.65/55.8 and for Oxygen 32.72/16. This gives a mole ratio of Fe:O as 1.53:2.04 or 3:4 Therefore the formula is Fe3O4
Itron has both 2 and 3 valencies int his compound
Fe3O4 is a compound. It is known as iron(II,III) oxide, where iron atoms are present in a combination of +2 and +3 oxidation states with oxygen.
Formula of 3 types of Iron oxides: Iron(II) oxide= FeO Iron(III) oxide= Fe2O3 Iron(II,III) oxide= Fe3O4
Fe3O4 (The numbers are subscripts, meaning they are smaller, and go beside the element.)
87.4%
91.6%
Fe + 2x Cl = Fe + Cl + Cl = 3 atoms per molecule.