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Well first things first you have to balance the equation

Fe3O4-->3Fe+2O2

Then because your given mass is in kg you have to convert it to grams

100.0kgx1,000kg/(over)1g=100,000g or 1.0x105

Next because you have mass of Fe3O4 you need to get the molar mass.

(3)55.85gFe+(4)16.00gO=231.55gFe3O4

Now convert grams to moles for your final answer

1.0x105gFe3O4x1mol/(over)231.55g(mm)x3molFe/(over)1mol Fe=1295.6 mol Fe

you can recover 1295.6moles of Fe from Fe3O4

If you follow the rule of Significant Figures, 100.0kg has 4 significant figures (digits) so your answer needs to have 4 digits

1295.6=1296

you can recover 1296 moles of Fe from Fe3O4

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How many grams of Fe3O4 are required to react completey with 300 grams of H2?

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