75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
25.0 grams Fe2O3 (1 mole Fe2O3/159.7 grams)(2 mole Fe/3 mole O)(111.7 grams /1 mole Fe)
= 11.7 grams of iron
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
No, iron oxide weighs more than pure iron. The iron will pick up the extra mass of the oxygen molecules that bond with it.
79 grams
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
It stays the same
155.5 grams of Fe are in 200.0 grams of FeO.
7.4 moles iron (55.85 grams/1 mole Fe) = 413.29 grams iron
s
Depends on the type of iron...
Fe23
No, iron oxide weighs more than pure iron. The iron will pick up the extra mass of the oxygen molecules that bond with it.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
23 grams iron ( 1mole Fe/55.85 grams) = 0.41 moles of iron
79 grams
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
Egon Eriksen has written: 'Conservation of iron recovered from the sea'
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.