0
What else can I help you with?
If a mixture of sand and salt weighing 74 grams is composed of 48 percent salt How many moles of salt are there?
To find the moles of salt in the mixture, we need to first determine the mass of salt present. Since the mixture is 48% salt, the mass of salt can be calculated as 74 grams * 0.48 = 35.52 grams. Next, we convert the mass of salt to moles using the molar mass of salt (NaCl), which is approximately 58.44 g/mol. Therefore, the number of moles of salt in the mixture is 35.52 grams / 58.44 g/mol ≈ 0.61 moles.
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
What compare 1 mole of H2 1 mole of O2 and 1 mole of F2?
Each mole of H2, O2, and F2 contains Avogadro's number of molecules, which is around 6.022 x 10^23. However, the molar masses of each gas are different: H2 is around 2 g/mol, O2 is around 32 g/mol, and F2 is about 38 g/mol. This means that 1 mole of H2 will weigh around 2 grams, 1 mole of O2 will weigh around 32 grams, and 1 mole of F2 will weigh around 38 grams.
What is the mass of NH4CL that must be dissolved in 200 grams of water 50 degree celsius to make a saturated solution?
The solubility of NH4Cl in water at 50°C is approximately 74 grams per 100 grams of water. To make a saturated solution, you would need to dissolve 148 grams of NH4Cl in 200 grams of water.
How do you work out the number of moles of unknown compound if you are only given the molar mass?
To find the number of moles from molar mass, divide the mass of the compound by its molar mass. The formula is: Moles = Mass (g) / Molar Mass (g/mol). This will give you the number of moles of the unknown compound.
How much does 74 grams of meat weigh in ounces?
2.61 ounces.
If a mixture of sand and salt weighing 74 grams is composed of 48 percent salt How many moles of salt are there?
To find the moles of salt in the mixture, we need to first determine the mass of salt present. Since the mixture is 48% salt, the mass of salt can be calculated as 74 grams * 0.48 = 35.52 grams. Next, we convert the mass of salt to moles using the molar mass of salt (NaCl), which is approximately 58.44 g/mol. Therefore, the number of moles of salt in the mixture is 35.52 grams / 58.44 g/mol ≈ 0.61 moles.
Justin weighs 74 kilograms How many grams does Justin weigh?
74,000 grams1 kg = 1000 grams74 kg = 74 kg * 1000 grams/1 kg = 74,000 grams
How many grams of Al2S3 can be formed from the reaction of 108.00 grams of Al with 5.00 grams of S?
The answer i got is 12.33 grams of Al2S3. Below i will try to show the steps i used: n=moles m=mass (grams) M= molecular weight (from periodic table) 2Al + 3S --> Al2S3 nAl= m/M = 9/13 = 0.692307 moles of Al nS= m/M = 8/16 = 0.5 moles of S Limiting Reagent: 1.5 moles of S required for every mole of Al (3:2 ratio) This means that there should be about 1.04 moles of S to completely use up all the Al. Since there is less than this amount of S present (only 0.5 moles), S is the limiting reagent and should be used in the mole calculation of the product Amount of product: 0.5 moles S x (1 mol Al2S3/ 3 mol S) = 0.16666 moles of Al2S3 nAl2S3 = m/M Molecular weight of Al2S3 = (2 x 13) + (3 x 16) = 74 0.16666 moles Al2S3 = m/74 m = 74 x 0.16666 = 12.33 grams of Al2S3 Therefore, 12.33 grams of Al2S3 is formed in this reaction ( hopefully this is right :P )
How many ounces are in 74 grams?
74 grams of water is equal to 74 milliliters of water. These type of conversions are the easiest to complete since they will always be equal to one another.
How much does potato bread weigh?
Potato may weigh anything between 100 to 110 grams or less depending on the size of the vegetable as a singular unit. Single potato can weigh up to 400 to 500 grams each. 74 to 75 % of the content of a potato is water and it is a good source of carbohydrates which measure up to 22.6 grams in each 100 grams of potato.
How many teaspoons is 74 grams?
There are approximately 15 teaspoons in 74 grams of a substance.
How many kilograms are there in 74 grams?
There are 1000 grams in one kilogram. Therefore, 7.4 grams is equal to 7.4/1000 = 0.0074 kilograms.
How many grams of KCl are required to prepare 2.25L of a 0.75m KCl solution?
To calculate the grams of KCl needed, first determine the molar mass of KCl (74.55 g/mol). Then use the formula: grams = molarity x volume (L) x molar mass. Plugging in the values, you get: grams = 0.75 mol/L x 2.25 L x 74.55 g/mol = 126.60 grams of KCl.
How many moles are in 74 g of KCl?
To find the number of moles in 74 g of KCl, you first need to calculate the molar mass of KCl. The molar mass of KCl is approximately 74.55 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 74 g / 74.55 g/mol ≈ 0.993 moles.
How many grams in 74 centigrams?
Move the decimal two places to the left. 74 cg= .74 g
If a compound is 26 percent nitrogen and 74 percent oxygen what is the emprical formula?
First you want to think "if I had 100 grams of this compound". If you do this, then you will be able to use the percentages as measurements in grams. Completing the sentence: "if I had 100 grams of this compound, then I would have 26 grams of nitrogen and 74 grams of oxygen". The next step is converting the grams to moles.Grams ÷ Atomic weight = moles26.0 grams ÷ 14.0 grams = 1.86 moles N74.0 grams ÷ 16.0 grams = 4.63 moles OThis is a ratio of 1.86:4.63 and is not recognizable as a small whole number ratio. (If this doesn't make sense, see the Law of Definite Proportions). In order to make the two numbers whole numbers, a trick is to divide both by the smallest number. Doing this will ensure that one number will always be 1.1.86 moles N ÷ 1.86 = 14.63 moles O ÷ 1.86 = 2.49Because the last digit is always uncertain to .02, we can say that 2.49 is actually 2.5. Now your ratio is 1:2.5, yet these are still not whole numbers. When you have an increment of .5, then multiply everything by 2.1:2.5 × 2 = 2:5 or 2 nitrogen : 5 oxygenYour final answer is N2O5
