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If a compound is 26 percent nitrogen and 74 percent oxygen what is the emprical formula?
First you want to think "if I had 100 grams of this compound". If you do this, then you will be able to use the percentages as measurements in grams. Completing the sentence: "if I had 100 grams of this compound, then I would have 26 grams of nitrogen and 74 grams of oxygen". The next step is converting the grams to moles.
Grams ÷ Atomic weight = moles
26.0 grams ÷ 14.0 grams = 1.86 moles N
74.0 grams ÷ 16.0 grams = 4.63 moles O
This is a ratio of 1.86:4.63 and is not recognizable as a small whole number ratio. (If this doesn't make sense, see the Law of Definite Proportions). In order to make the two numbers whole numbers, a trick is to divide both by the smallest number. Doing this will ensure that one number will always be 1.
1.86 moles N ÷ 1.86 = 1
4.63 moles O ÷ 1.86 = 2.49
Because the last digit is always uncertain to .02, we can say that 2.49 is actually 2.5. Now your ratio is 1:2.5, yet these are still not whole numbers. When you have an increment of .5, then multiply everything by 2.
1:2.5 × 2 = 2:5 or 2 nitrogen : 5 oxygen
Your final answer is N2O5
What else can I help you with?
What information is needed to calculate the percent composition of a compound?
The formula of the compound and the Atomic Mass of its elements.
What is the mass percent of nitrogen in ammonium carbonate?
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
How do you know when to solve for a empirical formula?
You should solve for an empirical formula when you are given the percent composition of elements in a compound or when you have the molar mass of the compound but not the molecular formula. The empirical formula provides the simplest whole-number ratio of atoms in a compound.
What is the mass percent of n in ammonium bicarbonate?
The formula for ammonium bicarbonate is NH4HCO3. To find the mass percent of nitrogen (N), calculate the molar mass of nitrogen in the formula and divide it by the molar mass of the entire compound NH4HCO3. The molar mass of N is 14.01 g/mol, and the molar mass of NH4HCO3 is 79.06 g/mol. Therefore, the mass percent of nitrogen in ammonium bicarbonate is (14.01 g/mol / 79.06 g/mol) * 100% = 17.7%.
What is the percent and the weight of nitrogen in 8.941 mol of ammonium sulfide?
Ammonium sulfide has the formula (NH4)2S, which contains 2 nitrogen atoms. One mole of (NH4)2S contains 2 moles of nitrogen. In 8.941 mol of (NH4)2S, there are 8.941 x 2 = 17.882 mol of nitrogen. To find the percent of nitrogen by weight, you would compare the molar mass of nitrogen to the molar mass of the compound and then multiply by 100.
What is the percent nitrogen in NH4NO3?
The percent nitrogen in NH4NO3 is 35.04%. This can be calculated by dividing the molar mass of nitrogen in the compound by the molar mass of the entire compound and then multiplying by 100.
What compound has a lower percent of mass by nitrogen- NO or N2O3?
The oxide N2O3 has a lower percent of mass nitrogen.
Percent age of nitrogen in urea and ammonia?
it can be calculated using the formula percentage composition of N =Gram molecular mass of nitrogen in the compound/ Gram molecular mass of compound *100
What is the percent composition of?
The gram Atomic Mass of cesium is 132.905 and that of nitrogen is 14.0067. The formula of the compound shows that there are three atoms of cesium for each atom of nitrogen. Therefore, the percent of cesium in the compound is: 100{3(132.905)/[3(132.905) + 14.0067]} or 96.6063 % cesium, to the justified number of significant digits. By difference the per cent nitrogen is 3.3937.
Empirical formula of a compound containing 60.3 percent magnesium and 39.7 percent oxygen?
The empirical formula of this compound would be MgO.
What information is needed to calculate the percent composition of a compound?
The formula of the compound and the Atomic Mass of its elements.
What is the method to calculate the percent nitrogen in these common fertilizers?
To calculate the percent nitrogen in common fertilizers, you can use the formula: Nitrogen (Amount of Nitrogen in fertilizer / Total weight of fertilizer) x 100. This formula helps determine the nitrogen content in the fertilizer, which is important for plant growth and health.
What is the mass percent of nitrogen in ammonium carbonate?
The molecular formula of ammonium carbonate is (NH4)2CO3. The molar mass of nitrogen in ammonium carbonate is 28.02 g/mol. The molar mass of ammonium carbonate is 96.09 g/mol. To calculate the mass percent of nitrogen in ammonium carbonate, you would divide the molar mass of nitrogen by the molar mass of the compound and multiply by 100. This gives a mass percent of nitrogen in ammonium carbonate of around 29.1%.
What is the emprical formula for the compound that contains 20 percent hydrogen and 80 percent carbon?
The atomic mass of hydrogen is 1 and that of carbon is 12, to the nearest integer. Therefore, a compound that contains 20 percent hydrogen and 80 percent carbon contains atoms of carbon in the ratio of 20:(80/12) = 20:(20/3) = 20 X 3/20 = 3. The smallest whole number ratio corresponding to this is 1:3, which corresponds to an empirical formula of CH3. (However, since carbon normally has a valence of 4 in hydrocarbons, the actual formula is probably C2H6.)
How do you calculate the percent by mass of NH3?
Grab yourself a periodic table and look up the atomic masses of nitrogen and hydrogen, which are the constituent elements of NH3 (which is ammonia.) Nitrogen is 14, and hydrogen is 1. Now look at the formula. It says you have 1 nitrogen and 3 hydrogens. Add it up: 14+1+1+1=17, for a total "molar mass" of 17 grams per mole. Now use the concept of percent (part divided by total) to get your percent composition by mass. 14/17=0.82, 82% nitrogen. 3/17=0.18, so 18% hydrogen. You can do that now for any compound!
What is the empirical formula for a compound that is 43.6 percent phosphorus and 56.4 percent oxygen?
p2o5
Calculate the empirical formula of a compound formed from 3 percent C 0.3 percent H and 96.7 percent you Which formula below correctly represents the empirical formula?
Chi a+
