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If a compound is 26 percent nitrogen and 74 percent oxygen what is the emprical formula?
Wiki User
∙ 14y ago
First you want to think "if I had 100 grams of this compound". If you do this, then you will be able to use the percentages as measurements in grams. Completing the sentence: "if I had 100 grams of this compound, then I would have 26 grams of nitrogen and 74 grams of oxygen". The next step is converting the grams to moles.
Grams ÷ Atomic weight = moles
26.0 grams ÷ 14.0 grams = 1.86 moles N
74.0 grams ÷ 16.0 grams = 4.63 moles O
This is a ratio of 1.86:4.63 and is not recognizable as a small whole number ratio. (If this doesn't make sense, see the Law of Definite Proportions). In order to make the two numbers whole numbers, a trick is to divide both by the smallest number. Doing this will ensure that one number will always be 1.
1.86 moles N ÷ 1.86 = 1
4.63 moles O ÷ 1.86 = 2.49
Because the last digit is always uncertain to .02, we can say that 2.49 is actually 2.5. Now your ratio is 1:2.5, yet these are still not whole numbers. When you have an increment of .5, then multiply everything by 2.
1:2.5 × 2 = 2:5 or 2 nitrogen : 5 oxygen
Your final answer is N2O5
Wiki User
∙ 14y ago
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