Depends on the type of iron...
1 mg of iron is equal to 0.001 grams of iron.
There are 0.35 grams of iron in 350 mg. To convert milligrams (mg) to grams (g), you can divide by 1000.
No, iron oxide weighs more than pure iron. The iron will pick up the extra mass of the oxygen molecules that bond with it.
Branflakes typically contain about 4.5 mg of iron per 30 grams.
To obtain one mole of iron atoms, you need to weigh out approximately 55.85 grams of iron. This is because the molar mass of iron (Fe) is about 55.85 grams per mole. Therefore, for one mole, you simply measure out this amount in grams.
The density of iron is 7.874 grams per cubic centimeter. Iron has the symbol Fe and the atomic number 26. The melting point of iron is 2,800.4 degrees Fahrenheit.
To calculate the number of grams of iron, you need to convert the number of iron atoms (6.02 x 10^23) into moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol). Then, multiply the number of moles of iron by the molar mass of iron (55.85 g/mol) to find the grams of iron. This would result in approximately 55.85 grams of iron.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
The molar mass of iron is 55.85 g/mol. To find the weight of 7.4 moles of iron, you would multiply the number of moles by the molar mass. Therefore, 7.4 moles of iron would weigh 7.4 moles * 55.85 g/mol = 411.49 grams.
155.5 grams of Fe are in 200.0 grams of FeO.
To find the number of moles in 1.5 grams of iron, you need to divide the mass of iron by its molar mass. The molar mass of iron is approximately 55.85 g/mol. So, 1.5 grams of iron is equal to 1.5 g / 55.85 g/mol = 0.027 moles of iron.
To determine the amount of iron needed to react with 40 grams of iron(III) oxide, you should use the stoichiometry of the reaction. Calculate the molar mass of iron(III) oxide (Fe2O3) and determine the molar ratio between iron and iron(III) oxide in the balanced chemical equation. From there, you can calculate the amount of iron needed to fully react with 40 grams of iron(III) oxide.