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The answer is 2080,46 g.

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This mass is 2,54 g.

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Q: What is the mass of 4.35x10-2 moles of sodium chloride?
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Which is the mass of 8 moles of sodium chloride?

Sodium chloride has a molar mass of about 58.5 g/mol. So multiply 8 moles by molar mass to get about 468 grams.


How many grams of sodium are needed to produce 5.3 moles of sodium chloride?

molecular formula for sodium chloride = NaClIf the mole (n) for NaCl = 5.3 moles, then the mole of sodium (Na) = 5.3 moles as well. 1 to 1 ratio mass = moles X molar mass m = 5.3 x 22.9 = 121.37 grams of sodium in 5.3 moles of sodium chloride


The formula of 20 moles of sodium chloride?

The chemical formula of sodium chloride is NaCl; formula is not dependent from the number of moles. Because the molecular mass of NaCl is 57,958 622 382, the mass of 20 moles is 1159,172 447 64.


How much moles are in the element sodium chloride?

Sodium chloride is a compound not an element; the molar mass of NaCl is 58,44 g.


What is the mass of sodium in 11.7 g of sodium chloride?

This question can be answered with the equation n = m ÷ M (where n is the number of mol's, m is te mass in grams and M is the Molar Mass of Sodium Chloride). Now, sodium chloride's molecular formula is written as, NaCl Now if we think of this formula as representing a ratio of elements within the compound, we can see that, NaCl : Cl = 1 mole of sodium chloride molecules : 1 mole of Chloride atoms So, as we know the mol ratio for this molecule, we can establish the mass of sodium in 11.7g of sodium chloride by first calculating the number of moles of Sodium chloride in 11.7g of the substance, so then moles = mass of sodium chloride ÷ Molar mass of sodium chloride = 11.7 ÷ 58.44277 = 0.20019584971759552122529442050745 moles (note that in stochiometry i personally prefer not to round numbers until the end of the question Now by applying this number to the mol ratio, we can calculate the number of moles of sodium in sodium chloride 1 mole of sodium chloride molecules : 1 mole of Chloride atoms =0.20019584971759552122529442050745 : 0.20019584971759552122529442050745 Now that we have established that the number of moles of of sodium in 11.7g of sodium chloride is 0.20019584971759552122529442050745 mol, the mass of sodium in 11.7g of sodium chloride can be calculated with the formula, m = n M = mass of sodium in 11.7g of sodium chloride = 0.20019584971759552122529442050745 X 23 = 4.6045045435046969881817716716713g (all decimal places)


How many moles in 22.6g of sodium chloride?

The formula mass of sodium chloride is 58.5 Amount of NaCl = 22.6/58.5 = 0.386mol


What is the mass of 1.2 x 10-3 moles of sodium chloride?

This mass is 69,6 mg.


How many grams is 8 moles of sodium chloride (NaCl)?

The mass is 467,52 g.


How many moles in 0.630gNaCl?

The formula mass of sodium chloride is 23.0 + 35.5 = 58.5 Amount of sodium chloride in a 0.630g pure sample = 0.0108mol


How many moles of sodium chloride (NaCl) are in 79.9 g of the compound?

79,9 g NaCl is equivalent to 1,367 moles.The formula mass of the compound sodium chloride, NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 79.9/58.5 = 1.37molThere are 1.37 moles of sodium chloride in a 79.9 gram pure sample of the compound.


How many grams of sodium chloride is obtained by the action of chlorine with 4 moles sodium?

A mole of an element or compound is 6.022 x 1023 (Avogadro's constant) molecules of that substance. This number is the number of molecules it takes for an amount of substance to have a mass in grams the same as its molecular mass: carbon has a molecular mass of 12, so 6.022 x 1023 (one mole) carbon atoms have a mass of 12 grams. The molecular mass of sodium is 23 (22.989) so one mole of sodium has a mass of 23 grams. Sodium chloride has a molecular mass of 58.44 so a mole of NaCl is 58.44 grams. One mole of sodium will make one mole of sodium chloride. Na + Cl => NaCl So four moles of sodium will make four moles of sodium chloride. 4Na + 4Cl => 4NaCl Four moles of NaCl has a mass of 4 x 58.44 = 233.76 grams.


How many moles of sodium chloride solute are in 155 grams of an 85.5 percent by mass solution?

2.27