0.25 mole of H2O
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
1 mole H2O = 18.02g H2O 3.2mol H2O x 18.02g/mol = 58g (rounded to two significant figures)
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
step 1; find # of moles 1.00*10^24 molecules x 1 mole of 6.02*10^23 molecules = 8.52*10^17 mole of H2O ( 1.0010*10^24 x 6.02*10^23 ) = 8.52*10^17 step 2 ; mass of H2O 8.52*10^17 mole x 18.02 grams per mole = 1.18*10^17 g H2O ( 8.52*10^17 x 18.02 ) = 1.18*10^17
0.25 mole of H2O
36g
The mass of NH3 mole = its molecular weight = 14 + 3 x 1 = 17 The mass of H2O mole = its molecular weight = 2 x 1 + 16 = 18 This means that one mole of NH3 weigh less than one mole of H2O
Divide mass of 27 g H2O by its molar mass of 18.0 g.mol−1 H2O and you get the number of moles: 1.5 mole H2O
Since the molar mass (grams per mole) of H2O is 18.02, the grams of H2O in 4 moles is 72.08g.
1 mole H2O = 18.02g H2O 3.2mol H2O x 18.02g/mol = 58g (rounded to two significant figures)
The molar mass of H2O =(2 atoms H x 1.00794g/mol H) + (1 atom O x 15.9994g/mol O) = 18.0152g/mol H2O1 mole of H2O = 18.0152g H2O1 mole of H2O molecules = 6.022 x 1023 molecules H2OConvert molecules to moles.5.00 x 102g H2O molecules x (1mole H2O/6.022 x 1023 molecules H2O) =8.31 x 10-22 mole H2OConvert moles to grams.8.31 x 10-22 mole H2O x (18.0152g H2O/1mole H2O) = 1.50 x 10-20g H2OAnswer: The mass in grams of 5.00 x 102g H2O molecules = 1.50 x 10-20g H2O
1 mole H2O = 18.015g H2O = 6.022 x 1023 molecules H2O 1.5 x 1023 molecules H2O x 18.015g H2O/6.022 x 1023 molecules H2O = 4.5g H2O
To teach you how to do this problem: 1. Look at the Periodic Table. O =16 grams/mole, H =1.01 grams/mole 2. Calculate the Molecular Weight of Water. 1*O + 2*H: 16+2.02=18.02g/mole 3. Divide the mass of what you have by the Molecular Weight: 35.1g H2O/(18.02 g H2O/mole H2O) 4. The units g H2O cancel leaving you with mole H2O. 5. 35.1 grams H2O= 1.95 moles H2O
I assume KOH is limiting. Balanced equation. KOH + HCl -> KCl + H2O 0.400 moles KOH (1 mole H2O/1 mole KOH)(18.016 grams/1 mole H2O) = 7.21 grams water produced =====================
1 mole H2O = 18.015g H2O = 6.022 x 1023 molecules H2O 1.5 x 1023 molecules H2O x 18.015g H2O/6.022 x 1023 molecules H2O = 4.5g H2O
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams.417 grams H2O / (18.0 grams) = .0232 moles H2O