Since the molar mass (grams per mole) of H2O is 18.02, the grams of H2O in 4 moles is 72.08g.
The answer is 36 g.
C2H4 + 3O2 -> 2CO2 +2H2O 50.0 grams C2H4 (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 mole CO2) = 157 grams CO2 produced
Since moles = mass/molar mass then the number of moles is 40.0/(1+1+16) = 2.22mol to 3sf
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
If all of th 120 g of glucose are converted to energy, how many grams of h2o and co2 will be produced?
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
Water has a molecuar mass of 18. This means it weights 18g per a mole. The molecular formula for water is H20. Your answer for how many moles in 1000 grams of water is 55.5084351.
C2H4 + 3O2 -> 2CO2 +2H2O 50.0 grams C2H4 (1 mole C2H4/28.052 grams)(2 mole CO2/1 mole C2H4)(44.01 grams/1 mole CO2) = 157 grams CO2 produced
Ratio of O2 to H20 after balancing equation is 1:2. 1:2 1.25:x.by cross multiplication x is 2.5 Mole =mass/mr.2.5×18(mr of h20) we get 27grams.
Since moles = mass/molar mass then the number of moles is 40.0/(1+1+16) = 2.22mol to 3sf
Each mole of a substance contains 6.022 E23 molecules or atoms of that substance. Four moles of H2O will contain 2.4088 E24 molecules.
For this you need the atomic (molecular) mass of H2O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. H2O= 18.0 grams500.0 grams H2O / (18.0 grams) = 27.8 moles H2O
.037g x 1 mole of H2O / 18.02g H2O= .00205 moles H20 this is a simple factor label problem in which you multiply the number of grams by the number of grams per mole. Thus, the GRAMS cancel and you are left with moles. 18.02 is the molecular weight of H2O; 1.01+1.01+16= 18.02 g/mol
Instead of waiting for the answer, I ended up solving it. lol 300grams of H20 X 110grams of KNO3/100 grams of H20 = 330 grams of KNO3 The grams of H20 both cancel out and leave you with 330 grams of KNO3 Containing the solubility of KNO3. At 60 degrees celsius the KNO3 grams were 110, which is (over) / 100grams of H20. Hope this helps with this workbook problem :)
the rule for solving amount of molecules is N(molecules)=6x10^23 x n(amount of mole) therefore there are 6x10^23 molecules in 1 mole of anything or in this case of H20
If all of th 120 g of glucose are converted to energy, how many grams of h2o and co2 will be produced?
C2H4 + H2O --> C2H5OHReaction balanced at 1:1:1 mole of each compound, so you'll need 0.132 mol C2H4 and this is equal to:0.132 (mol C2H4) * 28 (g/mol C2H4) = 3.696 g C2H4 = 3.70 g C2H4