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How many moles in180 grams of water?
180 grams of water is 10 moles of water.
How many moles of water do you have if you have 54.0 grams of water?
54,0 grams of water is equivalent to 3 moles.
How many moles of water ( dihydrogen oxide) are present in 75 grams?
75 grams water is equal to 4,166 moles.
If 1000 g of PCP are dissolved in 1000 L of water what is the concentration in terms of moles per liter?
The molar mass of PCP (phencyclidine) is 243.387 grams per mole. So 1000 g of PCP is equal to 4.108 moles. If that many moles is in 1000 liters, than the molarity (in moles per liter) is 4.108 ÷ 1000 = 0.0041 M
How many moles of water are there in 1.792 L?
95,474 moles
How many moles of water are present in 180 grams of water?
11
How many moles are in 27.8 grams of water?
To find the number of moles in 27.8 grams of water, you would first calculate the molar mass of water (18.015 g/mol). Then, divide the given mass by the molar mass to get the number of moles. In this case, 27.8 grams divided by 18.015 grams/mol is approximately 1.54 moles of water.
How many grams are in 1.5 moles of water?
There are approximately 27 grams in 1.5 moles of water.
How many moles of water H2O are produced from the reaction of 16 grams methane CH4 with an unlimited supply of oxygen O2. How many grams of H2O is this?
Two moles of water are produced.
How many hydrogen atoms are present in 3.65 grams of water?
3.65 grams of water is equal to .203 moles of H2O. This means there is also .203 moles of H2 present, or .408 grams.
How many grams of water are produced when 2.5 mil oxygen reacts with hydrogen?
When 2.5 moles of oxygen react with hydrogen, they react in a 1:2 ratio to produce water. Therefore, 2.5 moles of oxygen will produce 5 moles of water. To convert moles to grams, you'll need to know the molar mass of water, which is approximately 18 grams/mol. So, 2.5 moles of oxygen will produce 90 grams (5 moles x 18 grams/mole) of water.
How many moles of water molecules H2O are present in a 27 gram sample of water?
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
