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The formula for tin(II) fluoride is SnF2. The molar mass for that compound is 157g/mol, and its percent composition is 76% tin and 24% fluorine. (calculated from dividing the atomic masses by the total) So, if you have 24.6g of the compound, 24% by mass will be accounted for by the fluorine, and 24% OF 24.6g is about 5.9g of fluorine.

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Q: What is the mass of F in 24.6g of Tin II Flouride?
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