It's all about ratios and moles.
In 44g of CO2 32g is oxygen (2x16) and 12g is carbon (12). We can show that as a fraction 32/44 is oxygen.
Your question asks for the mass of oxygen in 7.38g. Lets call the mass x (I love algebra). We are looking for a mass, x, out of 7.38 and we know how the ratios work in another example. So we can say:
x/7.38 = 32/44
Or, in English, if 32 out of 44 is oxygen, how much oxygen is in 7.38?
We need to rearrange the equation to get x on it's own...
x/7.38 = 32/44
x = 32/44 *7.38
x= 5.37g
It's difficult to explain it on the internet. If you still don't get it then please talk to your teacher. It's their job to explain it!
This discussion will contain approximate values. Plug in the real values for a more accurate answer. One litre of petrol (gasoline for American readers) weighs about 800 grams. It is composed principally of carbon and hydrogen with a ratio of 2 carbon per 2 (and a bit) hydrogen or 24 units of mass carbon per 2 units of mass hydrogen. This means that for every 800 gm (one litre) of fuel you have (24/26)x800 = 738 grams of carbon. Since 1 carbon atom combines with 2 oxygen atoms each 12 gm carbon combines with 32 gm oxygen to make 44 gm Carbon dioxide. So for every litre of fuel (which weighs 800gm) you have 738 gm carbon and require 1969 grams of oxygen to combust it. This produces 738+1969= 2707 grams of CO2.
738 is DCCXXXVIII
734 / 738 = 99.4579946%
738 + 7 = 745
738 + 10 = 748
For a start, 738 is. Then there is 2*738 = 1476.
A sugar molecule does not have protons, neutrons, or electrons. It is composed of carbon, hydrogen, and oxygen atoms. The typical composition of a sugar molecule like glucose is 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms.
5984*738=4416192
257
773
82
738 ÷ 164 = 4.5