That depends on how much solution you have.
The mass of potassium chloride in a saturated solution will vary depending on the temperature and pressure. At room temperature, the solubility of potassium chloride in water is approximately 35.8 g/100 mL. Therefore, the mass of potassium chloride in a saturated solution can be calculated by considering the volume of the solution.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
The mass of potassium chloride (KCl) can be calculated by adding the masses of potassium and chloride together. So, it would be 39.1 amu (K) + 35.45 amu (Cl) = 74.55 amu.
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
To prepare a 40% potassium chloride solution in 100g of water, you would need to calculate the mass of potassium chloride required. Since the solution is 40% potassium chloride, that means 40g of the total solution mass must be potassium chloride. Therefore, you would need to add 40g of potassium chloride to the 100g of water to prepare the solution.
To make a 3 Molar solution of potassium chloride in 250 milliliters: Calculate the mass of potassium chloride needed using its molar mass. Dissolve this mass of potassium chloride in a small amount of water, then add water to bring the total volume to 250 ml. Stir to ensure complete mixing and dissolve the potassium chloride completely.
The saturated solution of sodium chloride is 379,3 g for 1 kg solution at 8o oC.
The mass of potassium chloride (KCl) can be calculated by adding the masses of potassium and chloride together. So, it would be 39.1 amu (K) + 35.45 amu (Cl) = 74.55 amu.
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
More than 45,5 g KNO3.
The solution was then cooled to 25 °C when solid potassium nitrate separated out to leave a saturated solution. Using the information provided in this question, what is the minimum mass of water that must now be added to the mixture of the solution and the solid in order to make this solid potassium nitrate redissolve at 25 °C?
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
The molecular mass of potassium (K) is approximately 39.1 g/mol, while the molecular mass of chlorine (Cl) is approximately 35.5 g/mol. Therefore, the molecular mass of potassium chloride (KCl) would be around 74.6 g/mol (39.1 + 35.5).
The mass percent of a saturated solution of NaNO3 at 20°C can be calculated by dividing the mass of NaNO3 in the saturated solution (82 g) by the total mass of the solution (82 g NaNO3 + 100 g water) and then multiplying by 100%. This results in a mass percent of 82/182 * 100% ≈ 45.1%.
The mass of the solution would be the sum of the mass of the sodium chloride and the mass of water. So, the mass of the solution would be 17.8 grams (NaCl) + 217 grams (water) = 234.8 grams.
100 g of the solution contains 11 g of sodium chloride