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About 0.013
Potassium (chemical symbol K) has atomic number 39.1. Amount of K in 449g sample = 449/39.1 = 11.5mol There are 11.5 moles of potassium in a 449g sample.
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
1.20442 x 1024 chloride ions
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Potassium has atomic number 39.1.Amount of K in 284g sample = 284/39.1 = 7.26molThere are 7.26 moles of potassium in a 284g sample.
About 0.013
Potassium (chemical symbol K) has atomic number 39.1. Amount of K in 449g sample = 449/39.1 = 11.5mol There are 11.5 moles of potassium in a 449g sample.
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
2.4088 x 1024 chloride ions
1.20442 x 1024 chloride ions
7: Molecules of HCl and KCl have the same number, 1, or chlorine atoms per mole; therefore, if HCl reacts completely with potassium, the same number of moles of potassium chloride as the number of moles of hydrogen chloride present will be formed. (For an ionic compound such as KCl, the term "formula unit" is preferable to "mole", but the mathematical consequences are the same.)
4.00 moles/2.00 L = 2.00 moles/L = 2.00 M
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K
The formula mass of sodium chloride is 23.0 + 35.5 = 58.5 Amount of sodium chloride in a 0.630g pure sample = 0.0108mol
The potassium hydroxide is what we call the limiting reactant. 4 moles of potassium hydroxide react with 2 moles of magnesium chloride. The third mole of magnesium chloride is in excess and has no effect.