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Potassium (chemical symbol K) has atomic number 39.1.

Amount of K in 449g sample = 449/39.1 = 11.5mol

There are 11.5 moles of potassium in a 449g sample.

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Related Questions

How many moles of potassium are contained in 449 g of potassium?

To determine the number of moles of potassium in 449 g, you need to divide the mass (449 g) by the molar mass of potassium (39.1 g/mol). This calculation would give you the number of moles of potassium in 449 g.


How many moles of potassium are contained in 449g of potassium?

To find the number of moles, you first need to calculate the molar mass of potassium (39.10 g/mol). Then, divide the given mass (449g) by the molar mass to get the number of moles. In this case, 449g of potassium would contain approximately 11.5 moles.


How many moles are in 12g of potassium?

12 g of potassium is equivalent to 0,307 moles.


How many grams are in 34.7 moles of potassium?

34,7 moles of potassium 1 356,7 g.


How many grams are in 2.2 moles of potassium sulfide?

242.594 g


How many moles are found in 15.6 g of potassium?

0.4g/mol


How many grams of potasium carbonate are in 1.5 moles of this substance?

1,5 moles of potassium carbonate have 276,41 g.


How many moles of potassium are in 156.4 g of potassium?

Well, darling, if you want to get technical, the molar mass of potassium is approximately 39.10 g/mol. So, if you have 156.4 g of potassium, you simply divide the given mass by the molar mass to find that you have about 4 moles of potassium. But hey, who's counting?


How many grams of potassium bromite (KBrO2) are there in 0.280 moles?

To calculate the grams of potassium bromite in 0.280 moles, you would multiply the number of moles by the molar mass of KBrO2, which is 119 g/mol. Therefore, 0.280 moles of KBrO2 would be 0.280 moles * 119 g/mol = 33.32 grams.


How many grams of potassium permanganate are in 2.20 moles?

To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.


How many grams of oxgyen will be in two moles of potassium dichromate?

The answer is 224,24 g oxygen.


How many moles of potassium chloride are there in a 100.0g sample of potassium chloride?

To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.