Potassium (chemical symbol K) has atomic number 39.1.
Amount of K in 449g sample = 449/39.1 = 11.5mol
There are 11.5 moles of potassium in a 449g sample.
224 g are in two moles of potassium dichromate.
1,5 moles of potassium carbonate have 276,41 g.
This mass is 42,28 g.
Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed
449 g K x 1 mole K/39 g K = 11.5 moles (3 sig figs)
449 (g K) / 39.1 (g/mol K) = 11.5 mol K
12 g of potassium is equivalent to 0,307 moles.
34,7 moles of potassium 1 356,7 g.
224 g are in two moles of potassium dichromate.
242.594 g
0.4g/mol
1,5 moles of potassium carbonate have 276,41 g.
The answer is 224,24 g oxygen.
This mass is 42,28 g.
Molecular weight of potassium (K): 39.1 g/mole...Just divide 156 by the molecular weight to get moles:156/39.1 = 3.99 moles K
You have2KClO3 ==> 2KCl + 3O2 as the balanced equation 25 g KClO3 x 1 mole/123 g = 0.20 moles moles KCl formed = 0.20 moles KClO3 x 2 moles KCl/2 moles KClO3 = 0.20 moles KCl formed grams KCl = 0.20 moles x 74.5 g/mole = 14.9 g = 15 grams of KCl formed